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为什么在访问其他 $_POST 元素之前检查 if isset($_POST['Submit']) ？

发布于 2024-10-29 15:01:14 字数 417 浏览 6 评论 0 原文

这段代码是做什么的？如果是 Isset，变量在做什么，那么 $_POST 在做什么？有人可以解释一下吗？

if (isset($_POST['Submit'])) {
    $title=$_POST['title'];
    $forename = $_POST['forename']; 
    $surname=$_POST ['surname'];
    $dateofbirth=$_POST ['dateofbirth'];
    $gender=$_POST ['gender'];
    $email=$_POST['email']; 
    $phone=$_POST['phone'];
    $passcode1=$_POST ['passcode1'];
    $passcode2=$_POST ['passcode2'];

原文

What is this code doing? If Isset, and what are the variables doing, whats the $_POST doing? Can someone explain please?

if (isset($_POST['Submit'])) {
    $title=$_POST['title'];
    $forename = $_POST['forename']; 
    $surname=$_POST ['surname'];
    $dateofbirth=$_POST ['dateofbirth'];
    $gender=$_POST ['gender'];
    $email=$_POST['email']; 
    $phone=$_POST['phone'];
    $passcode1=$_POST ['passcode1'];
    $passcode2=$_POST ['passcode2'];

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堇年纸鸢 2024-11-05 15:01:14

$_POST 包含用户提交的表单中的数据。

if(isset($_POST['Submit']))

正在检查表单是否已提交。可能存在具有此名称的隐藏元素，或者创建提交按钮以包含此值。

其余行将*1 POST 超级全局信息复制到更易于使用的变量中。

（*1 并未实际复制，PHP 是写入时复制）

$_POST contains the data from the form the user submitted.

if(isset($_POST['Submit']))

is checking to see if a form was submitted. There is likely a hidden element with this name, or the submit button was created to include this value.

The remainder of the lines copy*1 the information out of the POST super global into easier to use variables.

(*1 not actually copied, PHP is copy on write)

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轮廓§ 2024-11-05 15:01:14

如果正在提交表单，则会分配变量。

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混吃等死 2024-11-05 15:01:14

它将检查表单是否已提交，并将 html 元素的值设置为 PHP 变量。

这些变量可用于进一步处理并随后存储在数据库中。

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梦毁影碎の 2024-11-05 15:01:14

因此，这是尝试回答您的无定形问题。

if (isset($_POST['Submit']))

此行检查 $_POST 数组中是否存在名为“Submit”的条目。
isset 是一个检查 PHP 中变量是否存在的函数。

$_POST 是 PHP 中的一个全局变量，用于捕获在 HTTP POST 请求中发送的键值对。在 99% 的用例中，$_POST 将包含 HTML 表单提交的结果。

$title=$_POST['title'];

将 PHP 脚本中的 title 变量设置为 post 数组中的 title 字段。标题可能是表单提交的文本字段。

查看示例代码中 $_POST 的使用，对 php 脚本的请求可能来自如下所示的表单：

<form method="post" name="someForm" action="thatScript.php">
<input type="text" name="title"/>
<input type="text" name="forename"/>
<input type="text" name="surname"/>
... other inputs that correspond to $_POST entries...
<input type="submit" value="Submit" name="Submit"/> <!-- the submit field that is checked in the isset -->
</form>

注意：



这告诉浏览器在发布请求中提交表单的键值对。如果该行读取  那么浏览器将提交键值对作为 get 请求，并且 php 脚本将检查并使用 $_GET而不是 $_POST。

So here is an attempt to answer your amorphous question.

if (isset($_POST['Submit']))

This line is checking to see if an entry called 'Submit' is present in the $_POST array.
isset is a function that checks the existence of variables in PHP.

$_POST is a global variable in PHP that captures the key-value pairs sent in an HTTP POST request. $_POST will contain the result of an HTML form submission in 99% of the use cases.

$title=$_POST['title'];

is setting the title variable in the PHP script to the title field in the post array. title was probably a text field submitted by a form.

Looking at the use of $_POST in your example code, the request to the php script probably comes from a form that looks like:

<form method="post" name="someForm" action="thatScript.php">
<input type="text" name="title"/>
<input type="text" name="forename"/>
<input type="text" name="surname"/>
... other inputs that correspond to $_POST entries...
<input type="submit" value="Submit" name="Submit"/> <!-- the submit field that is checked in the isset -->
</form>

Notice: <form method="post"
This tells the browse to submit the key-value pairs for the form in a post request. If that line read <form metho="get" then the browse would submit the key-value pairs as a get request and the php script would check and use $_GET instead of $_POST.