计算文件中单词的音节数的代码
到目前为止，我有以下代码来计算 cmudict（CMU 发音词典）中单词的音节数。它计算字典中所有单词的音节数。现在我需要用输入文件替换 cmudict 并查找作为输出打印的文件中每个单词的音节数。仅以读取模式打开输入文件是行不通的，因为 dict() 无法作为文件的属性提供。 代码如下：
from curses.ascii import isdigit
from nltk.corpus import cmudict
d = cmudict.dict() # get the CMU Pronouncing Dict
def nsyl(word):
"""return the max syllable count in the case of multiple pronunciations"""
return max([len([y for y in x if isdigit(y[-1])]) for x in d[word.lower()]])
w_words = dict([(w, nsyl(w)) for w in d.keys() if w[0] == 'a'or'z'])
worth_abbreviating = [(k,v) for (k,v) in w_words.iteritems() if v > 3]
print worth_abbreviating 有人可以帮我吗？
I have the following piece of code so far to count the number of syllables in the words in the cmudict ( CMU pronunciation dictionary). It counts the number of syllables for all the words in the dictionary. Now I need to replace cmudict with my input file and find the number of syllables for each word in the file which is printed as output. Just opening the input file in read mode does not work as dict() cannot be provided as the attribute to the file.
The code is given below :
from curses.ascii import isdigit
from nltk.corpus import cmudict
d = cmudict.dict() # get the CMU Pronouncing Dict
def nsyl(word):
"""return the max syllable count in the case of multiple pronunciations"""
return max([len([y for y in x if isdigit(y[-1])]) for x in d[word.lower()]])
w_words = dict([(w, nsyl(w)) for w in d.keys() if w[0] == 'a'or'z'])
worth_abbreviating = [(k,v) for (k,v) in w_words.iteritems() if v > 3]
print worth_abbreviating Can anyone please help me out?
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不确定这是否能解决整个问题，但是：
可能应该是
因为
if w[0] == 'a'or'z'意味着if (w[0] == 'a ') 或 ('z')。字符串'z'为 True，因此条件始终为 True。例如，
Not sure this will solve the whole problem, but:
should probably be
since
if w[0] == 'a'or'z'meansif (w[0] == 'a') or ('z'). The string'z'is Truish, so the condition is always True.For example,