如何在 toString 方法中获取多项式中的符号？

发布于 2024-10-29 13:05:18 字数 773 浏览 5 评论 0原文

我想将带有系数 getA()、getB() 和 getC() 的多项式与 +ve 或 -ve 符号相加。并删除零 coff 的项，例如 2x^2+5，而不是一般的 2x^2+0x+5，例如 (+/-)ax^2(+/-)bx(+/-)c。

public String toString() {

    if (getA().equals(DEFAULT_A)
        && getB().equals(DEFAULT_B)
        && getC().equals(DEFAULT_C)) {
        return "0";
    } else {
        String poly = "";
        if (!getA().equals(DEFAULT_A)) {
            poly = getA().toString() + "x^2";
        }
        if (!getB().equals(MyDouble.zero)) {
            if (getB().compareTo(MyDouble.zero)) {
                return getB();
            }
        }
        poly += getB().toString() + "x";
        if (!getC().equals(MyDouble.zero)) {
            poly += getC().toString;
        }

        return poly;
    }
}

原文

i want to add the polynomials with the coeff getA(),getB() and getC() with the +ve or -ve signs. and remove the terms with zero coff like 2x^2+5 not 2x^2+0x+5 in general like (+/-)ax^2(+/-)bx(+/-)c.

public String toString() {

    if (getA().equals(DEFAULT_A)
        && getB().equals(DEFAULT_B)
        && getC().equals(DEFAULT_C)) {
        return "0";
    } else {
        String poly = "";
        if (!getA().equals(DEFAULT_A)) {
            poly = getA().toString() + "x^2";
        }
        if (!getB().equals(MyDouble.zero)) {
            if (getB().compareTo(MyDouble.zero)) {
                return getB();
            }
        }
        poly += getB().toString() + "x";
        if (!getC().equals(MyDouble.zero)) {
            poly += getC().toString;
        }

        return poly;
    }
}

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全部不再 2024-11-05 13:05:18

对于普通双打来说，这会简单得多，这可能会让您知道可以做什么。

public static String poly(double a, double b, double c) {
    return (a == 0 ? "" : toNum(a) + "x^2 ") +
            (b > 0 ? "+" : "") +
            (b == 0 ? "" : toNum(b) + "x ") +
            (c > 0 ? "+" : "") +
            (c == 0 ? "" : c == 1 ? "1" : c == -1 ? "-1" : toNum(c));
}

private static String toNum(double v) {
    return v == 1 ? "" : v == -1 ? "-" : 
           v == (long) v ? Long.toString((long) v) : Double.toString(v);
}

public static void main(String... args) {
    System.out.println(poly(1, 1.5, 2.5));
    System.out.println(poly(-1, -1, -1));
    System.out.println(poly(2, 0, 0));
    System.out.println(poly(0, -3, 0));
    System.out.println(poly(0, 0, -9));
}

印刷

x^2 +1.5x +2.5
-x^2 -x -1
2x^2 
-3x 
-9

This would be alot simpler with plain doubles, This may give you an idea of what you can do.

public static String poly(double a, double b, double c) {
    return (a == 0 ? "" : toNum(a) + "x^2 ") +
            (b > 0 ? "+" : "") +
            (b == 0 ? "" : toNum(b) + "x ") +
            (c > 0 ? "+" : "") +
            (c == 0 ? "" : c == 1 ? "1" : c == -1 ? "-1" : toNum(c));
}

private static String toNum(double v) {
    return v == 1 ? "" : v == -1 ? "-" : 
           v == (long) v ? Long.toString((long) v) : Double.toString(v);
}

public static void main(String... args) {
    System.out.println(poly(1, 1.5, 2.5));
    System.out.println(poly(-1, -1, -1));
    System.out.println(poly(2, 0, 0));
    System.out.println(poly(0, -3, 0));
    System.out.println(poly(0, 0, -9));
}

prints