在 iPhone 上按字母顺序对 ABRecord 进行排序

发布于 2024-10-29 08:08:02 字数 631 浏览 3 评论 0原文

我正在使用以下代码检索联系人姓名：

for( int i = 0 ; i < n ; i++ )
{
    Contact *c = [[Contact alloc] init];

    ABRecordRef ref = CFArrayGetValueAtIndex(all, i);
    NSString *firstName = (NSString *)ABRecordCopyValue(ref, kABPersonFirstNameProperty);
    NSString *lastName = (NSString *)ABRecordCopyValue(ref, kABPersonLastNameProperty);
    c.firstName = firstName; //[NSString stringWithFormat:@"%@ %@", firstName, lastName];
    c.lastName = lastName;

    [contacts addObject:c];

    [c release];
}

有人知道按字母顺序排序此列表的方法吗？我读过有关 sortedArrayUsingSelector:@selector(compare:) 但我不知道它是如何工作的。

原文

I'm retrieving contact names with this code:

for( int i = 0 ; i < n ; i++ )
{
    Contact *c = [[Contact alloc] init];

    ABRecordRef ref = CFArrayGetValueAtIndex(all, i);
    NSString *firstName = (NSString *)ABRecordCopyValue(ref, kABPersonFirstNameProperty);
    NSString *lastName = (NSString *)ABRecordCopyValue(ref, kABPersonLastNameProperty);
    c.firstName = firstName; //[NSString stringWithFormat:@"%@ %@", firstName, lastName];
    c.lastName = lastName;

    [contacts addObject:c];

    [c release];
}

Does anyone know a way of ordering this list alphabetically? I've read about sortedArrayUsingSelector:@selector(compare:) but I have no idea how that is supposed to work.

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苏大泽ㄣ 2024-11-05 08:08:02

NSSortDescriptor *mySorter = [[NSSortDescriptor alloc] initWithKey:@"lastName" ascending:YES];
[contacts sortUsingDescriptors:[NSArray arrayWithObject:mySorter]];
[mySorter release];

NSSortDescriptor *mySorter = [[NSSortDescriptor alloc] initWithKey:@"lastName" ascending:YES];
[contacts sortUsingDescriptors:[NSArray arrayWithObject:mySorter]];
[mySorter release];

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稚然 2024-11-05 08:08:02

此方法将让您尊重用户按名字或姓氏排序的偏好。

contacts = (bridgedPeople as [ABRecord]).sort {
    (person1, person2) -> Bool in
    return .CompareLessThan == ABPersonComparePeopleByName(person1, person2, ABPersonGetSortOrdering())
}

专业提示：将您要排序的名称部分加粗；否则，当您混合具有[没有名字，没有姓氏，名字和姓氏]的联系人时，会变得混乱

This method will let you respect the user's preferences for sorting by first or last name.

contacts = (bridgedPeople as [ABRecord]).sort {
    (person1, person2) -> Bool in
    return .CompareLessThan == ABPersonComparePeopleByName(person1, person2, ABPersonGetSortOrdering())
}

Pro-tip: Boldface the part of the name that you're sorting on; otherwise it gets confusing when you mix contacts who have [no first name, no last name, first and last name]

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