为什么这不起作用（javascript + 音频播放器）

发布于 2024-10-29 04:26:09 字数 1106 浏览 1 评论 0原文

我正在尝试在我的网站上使用 JavaScript 音频播放器（http://wpaudioplayer.com/standalone/）。我尝试将 PHP 变量传递到 JavaScript，但它似乎无法正常工作。 JavaScript 将 html 段落替换为匹配的 id 到 flash mp3 播放器中。

编辑：更新了问题

如果我直接传递 url，mp3 播放器会播放，但当我通过变量传递它时，它不会播放。

这有效

<p id="audioplayer_<?php echo $i ?>">Install flash to use mp3 player</p>
            <script type="text/javascript">  
            var id = "audioplayer_" + <?php echo $i ?>;             
        AudioPlayer.embed(id, {soundFile: "http://site.com/mp3file.mp3"});  
        </script>

但这不起作用

 <p id="audioplayer_<?php echo $i ?>">Install flash to use mp3 player</p>
                <script type="text/javascript">  
                var id = "audioplayer_" + <?php echo $i ?>; 
                var url = "<?php echo $url ?>";             
            AudioPlayer.embed(id, {soundFile: url});  
            </script>

$url 变量的值为 http://site.com/mp3file.mp3

原文

I am trying to use the JavaScript audio player(http://wpaudioplayer.com/standalone/) on my website. I tried passing PHP variables into the JavaScript but it does not seem to work properly. The JavaScript replaces the html paragraph with a matching id into a flash mp3 player.

EDIT: Updated the issue

If I pass the url directly, the mp3 player plays but when I pass it through a variable it does not.

This works

<p id="audioplayer_<?php echo $i ?>">Install flash to use mp3 player</p>
            <script type="text/javascript">  
            var id = "audioplayer_" + <?php echo $i ?>;             
        AudioPlayer.embed(id, {soundFile: "http://site.com/mp3file.mp3"});  
        </script>

But this does not

 <p id="audioplayer_<?php echo $i ?>">Install flash to use mp3 player</p>
                <script type="text/javascript">  
                var id = "audioplayer_" + <?php echo $i ?>; 
                var url = "<?php echo $url ?>";             
            AudioPlayer.embed(id, {soundFile: url});  
            </script>

The value of the $url variable is http://site.com/mp3file.mp3

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空气里的味道 2024-11-05 04:26:09

您忘记在 url 两边加上引号，因为对于 JavaScript 来说它是一个字符串。将您的 PHP 代码更改为

<p id="audioplayer_<?php echo $i ?>">Install flash to use mp3 player</p>
        <script type="text/javascript">  
        var i = <?php echo $i ?>;
        var url = "<?php echo $url ?>";
    AudioPlayer.embed("audioplayer_" + i, {soundFile: url});  
    </script>

You forgot to put quotes around the url, because to JavaScript it is a string. Change your PHP code to

<p id="audioplayer_<?php echo $i ?>">Install flash to use mp3 player</p>
        <script type="text/javascript">  
        var i = <?php echo $i ?>;
        var url = "<?php echo $url ?>";
    AudioPlayer.embed("audioplayer_" + i, {soundFile: url});  
    </script>

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血之狂魔 2024-11-05 04:26:09

如果您在任何其他地方不需要变量，请不要使用它们并尝试

<p id="audioplayer_<?php echo $i ?>">Install flash to use mp3 player</p>
<script type="text/javascript">  
AudioPlayer.embed("audioplayer_<?php echo $i; ?>", {soundFile: "<?php echo $url; ?>"});  
</script>

使用此代码，以避免“变量问题”

If you do not need the variables at any other place, don't use them and try this

<p id="audioplayer_<?php echo $i ?>">Install flash to use mp3 player</p>
<script type="text/javascript">  
AudioPlayer.embed("audioplayer_<?php echo $i; ?>", {soundFile: "<?php echo $url; ?>"});  
</script>

with this code you avoid "variable issues"

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