替换 Rails 3 中资源的默认路由
我有一个像这样定义的资源：
resources :referrals, :except => [:show, :edit, :destroy]
并且我想替换（不仅仅是添加命名路由）Rails生成的默认路由，特别是用于更新的路由行动。
这是我的 rake 路线：
referrals GET /referrals(.:format) {:action=>"index", :controller=>"referrals"}
POST /referrals(.:format) {:action=>"create", :controller=>"referrals"}
new_referral GET /referrals/new(.:format) {:action=>"new", :controller=>"referrals"}
referral PUT /referrals/:id(.:format) {:action=>"update", :controller=>"referrals"}
share /share(.:format) {:controller=>"referrals", :action=>"new"}
special /special(.:format) {:controller=>"referrals", :action=>"index"}
thanks /thanks(.:format) {:controller=>"pages", :action=>"thanks"}
/:shortlink(.:format) {:controller=>"referrals", :action=>"update"}
/:linktext(.:format) {:controller=>"referrals", :action=>"update"}
root /(.:format) {:controller=>"pages", :action=>"home"}
我想要 或
/:shortlink(.:format)
来
/:linktext(.:format)
执行更新操作，但不
/referrals/:id(.:format)
这是为了实现一种非密码“安全”形式。当 PUT 进行更新操作时，我希望发生某些事情，但我不想要求授权才能执行此操作，并且我不想允许根据控制器名称和简单的低值轻松猜测 url编号 id。
如何完全替换 Rails 给出的默认路线？
I have a resource defined like so:
resources :referrals, :except => [:show, :edit, :destroy]
and I'd like to replace (not just add a named route) a default route that Rails produces, specifically the one for the update action.
Here is my rake routes:
referrals GET /referrals(.:format) {:action=>"index", :controller=>"referrals"}
POST /referrals(.:format) {:action=>"create", :controller=>"referrals"}
new_referral GET /referrals/new(.:format) {:action=>"new", :controller=>"referrals"}
referral PUT /referrals/:id(.:format) {:action=>"update", :controller=>"referrals"}
share /share(.:format) {:controller=>"referrals", :action=>"new"}
special /special(.:format) {:controller=>"referrals", :action=>"index"}
thanks /thanks(.:format) {:controller=>"pages", :action=>"thanks"}
/:shortlink(.:format) {:controller=>"referrals", :action=>"update"}
/:linktext(.:format) {:controller=>"referrals", :action=>"update"}
root /(.:format) {:controller=>"pages", :action=>"home"}
I'd like either the
/:shortlink(.:format)
or
/:linktext(.:format)
to hit the update action, but not the
/referrals/:id(.:format)
This is to implement a form of non-password "security". When the PUT goes to the update action, I want certain things to happen, but I don't want to require authorization to do this, and I don't want to allow easy guessing of the url based on controller name and simple low-numbered ids.
How can I fully replace the default route given by rails?
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（1）
资源：推荐，：例外 => [:show, :edit, :destroy, :update]匹配“/whatever_you_want/:variable_here”=> "referrals#updated", :as=> the_link, :via=> :put访问参数
然后在你的控制器中，你将使用
params[:variable_here]，这里的参数是你想要在数据库中比较的任何内容，路径将像这样创建:
the_link_path或the_link_url:via 部分将限制每个 HTTP 方法的路径，因此只有 put 请求才会
在此处匹配更多信息
http://guides.rubyonrails.org/routing.html
resources :referrals, :except => [:show, :edit, :destroy, :update]match "/whatever_you_want/:variable_here" => "referrals#updated", :as=> the_link, :via=> :putthen in your controller you will access the param with
params[:variable_here]here the param is whatever you want to compare against in the db, and the path will be create like this:
the_link_pathorthe_link_urlthe :via part will constrain the path per HTTP method so only put request will match
more info here
http://guides.rubyonrails.org/routing.html