判断长/纬度是否在矩形内

发布于 2024-10-29 02:31:51 字数 316 浏览 3 评论 0原文

给定左上角的长/纬度和右下角的长/纬度，我如何找出给定的长/纬度是否落在矩形内？

理想情况下，我会查看类似

bool IsWithinArea(float topLeftLat,float topLeftLong,
   float bottomRightLat,float bottomRightLong,float testLat,float testLong)

Update 的

内容。一个问题是，从长/纬度创建的矩形可能来自旋转的地图，因此右下角并不总是大于左上角......

原文

Given a top-left long/lat and a bottom-right long/lat how can i find out if a given long/lat falls within the rectangle ?

Ideally i would be looking at something like

bool IsWithinArea(float topLeftLat,float topLeftLong,
   float bottomRightLat,float bottomRightLong,float testLat,float testLong)

Update

The one problem is that the rectangle created from the long/lat may be from a rotated map, so bottom right will not always be greater than top left...

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

愛放△進行李 2024-11-05 02:31:51

我们可以让它比琐碎的检查更有趣：

return new Rect(topLeftLat, topLeftLong, bottomRightLat - topLeftLat, bottomRightLong - topLeftLong)
      .Contains(testLat, testLong);

PS： Rect.Contains(... ）方法

We can make it more interesting than trivial checks:

return new Rect(topLeftLat, topLeftLong, bottomRightLat - topLeftLat, bottomRightLong - topLeftLong)
      .Contains(testLat, testLong);

P.S.: Rect.Contains(...) method

回复收藏 0 原文

梦幻的心爱 2024-11-05 02:31:51

不确定我是否想简单

bool IsWithinArea(float topLeftLat, float topLeftLong, float bottomRightLat, float bottomRightLong, float testLat, float testLong)
{
    return (testLat >= topLeftLat && testLat <= bottomRightLat && testLong >= topLeftLong && testLong <= bottomRightLong);
}

Not sure if I'm thinking to simple

bool IsWithinArea(float topLeftLat, float topLeftLong, float bottomRightLat, float bottomRightLong, float testLat, float testLong)
{
    return (testLat >= topLeftLat && testLat <= bottomRightLat && testLong >= topLeftLong && testLong <= bottomRightLong);
}

回复收藏 0 原文

夏至、离别 2024-11-05 02:31:51

假设 Lat 是 x 坐标，Long 是 y 坐标，并且还假设坐标系的原点位于左上角：

public bool IsWithinArea(float topLeftLat,float topLeftLong,
       float bottomRightLat,float bottomRightLong,float testLat,float testLong) {

          return (testLat >= topLeftLat && testLat <= bottomRightLat && testLong >= topLeftLong && testLong <= bottomRightLong);

    }

Assuming that Lat is the x coordinate und Long is the y coordinate and also assuming that the coordinate systems has its origin at the left top:

public bool IsWithinArea(float topLeftLat,float topLeftLong,
       float bottomRightLat,float bottomRightLong,float testLat,float testLong) {

          return (testLat >= topLeftLat && testLat <= bottomRightLat && testLong >= topLeftLong && testLong <= bottomRightLong);

    }

回复收藏 0 原文