如何从 Type.GUID 创建对象
我有一组继承自同一基类的类，我需要创建一个工厂方法，用于基于附加到实现类的 GuidAttribute 来实例化不同的基类实现。所以基本上情况是这样的：
abstract class Foo
{
/* ... */
public static Foo Create(Guid guid) {
Type type;
// Resolve the type ?
return Activator.CreateInstance(type) as Foo;
}
}
[Guid("<guid1>")]
class Bar : Foo { ... }
[Guid("<guid2>")]
class Baz : Foo { ... }
除了迭代加载的程序集中的所有类型并缓存结果之外，还有其他方法吗？
I have a set of classes that inherit from the same base class and I need to create a factory method for instantiation of the different base class implementations based on the GuidAttribute attached to the implementing class. So basically the scenario is like this:
abstract class Foo
{
/* ... */
public static Foo Create(Guid guid) {
Type type;
// Resolve the type ?
return Activator.CreateInstance(type) as Foo;
}
}
[Guid("<guid1>")]
class Bar : Foo { ... }
[Guid("<guid2>")]
class Baz : Foo { ... }
Is there any other way than iterating all the types in the loaded assemblies and caching the results?
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评论（2）
它不会是自动的，但您可以简单地构建一个
Dictionary或者如果每个程序集（ala 插件架构）中有一个公共接口/类，则请求它相应地注册类型。没有必要对所有事情都使用反射:)我发现它在很多情况下不太优雅。
It wouldn't be automatic but you could simply build a
Dictionary<Guid,Type>or if there's a common interface/class in each assembly (ala plugin architecture) request it register the types accordingly.There's no need to use reflection for everything :) I find it less elegant in many cases.
我不认为还有其他方法。当然，我就是这么做的。
I don't think there is another way. Certainly, that is how I would do it.