php新手问题：正则表达式

发布于 2024-10-28 14:25:20 字数 581 浏览 9 评论 0原文

抱歉，我已经提出了这个要求，但尚未找到解决方案:( 这是我的字符串：（如您所见，它有换行符）

Webname:    [webname]
Username:   [username]
IP:     [IP]

我需要读出方括号内的值。这是我的代码：

    $pattern = '/\[(.|\n)+?\]/'; // i've used the same syntax for my asp projects, always worked
    preg_match($pattern, $txt, $matches, PREG_OFFSET_CAPTURE);
    echo "matches:".count($matches)."\n\n";
    foreach ($matches as $match) 
    {
        echo $match[0]."\n";
    }

我只得到 2 个匹配项：[webname] 和 e (???) 我已经摆弄这个好几个小时了，无法找出问题所在..

有什么想法吗？谢谢

原文

i'm sorry i've already asked for this but couldn't find a solution yet :(
here's my string: (as you can see it has linebreaks)

Webname:    [webname]
Username:   [username]
IP:     [IP]

i need to read out the values inside the square brackets.
here's my code:

    $pattern = '/\[(.|\n)+?\]/'; // i've used the same syntax for my asp projects, always worked
    preg_match($pattern, $txt, $matches, PREG_OFFSET_CAPTURE);
    echo "matches:".count($matches)."\n\n";
    foreach ($matches as $match) 
    {
        echo $match[0]."\n";
    }

i'm getting only 2 matches: [webname] and e (???)
i'm fiddling with this for hours now and can't find out what's wrong ..

any ideas?
thanks

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深空失忆 2024-11-04 14:25:20

看起来比实际情况更复杂。换行符在这里不起作用。

$pattern = '/\[(.+?)\]/';
preg_match_all($pattern, $txt, $matches);

print_r($matches);

给出

Array
(
    [0] => Array
        (
            [0] => [webname]
            [1] => [username]
            [2] => [IP]
        )

    [1] => Array
        (
            [0] => webname
            [1] => username
            [2] => IP
        )

)

所以值将在 $matches[1] 中。如果您想要包含括号的值 ($matches[0])，您也可以在模式中省略括号。

Looks more complicated than it has to be. Line breaks don't play any role here.

$pattern = '/\[(.+?)\]/';
preg_match_all($pattern, $txt, $matches);

print_r($matches);

gives

Array
(
    [0] => Array
        (
            [0] => [webname]
            [1] => [username]
            [2] => [IP]
        )

    [1] => Array
        (
            [0] => webname
            [1] => username
            [2] => IP
        )

)

So the values would be in $matches[1]. If you want the values including the brackets ($matches[0]), you can also omit the parenthesis in the pattern.

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人生戏 2024-11-04 14:25:20

第一个捕获组（在您的情况下只有一个）位于 $matches[1] 中

回复收藏 0 原文

把时间冻结 2024-11-04 14:25:20

尝试类似的方法

$pattern = '/\[([^\]]+)\]/';

并使用 preg_match_all() 来获取所有匹配项。

Try something like

$pattern = '/\[([^\]]+)\]/';

and use preg_match_all() to get all matches.

回复收藏 0 原文

赠意 2024-11-04 14:25:20

试试这个

$values = array();

foreach (explode("\n", $text) as $line) {
    if (preg_match('/([^:]++):[^\s]*+(.*+)/', $line, $match)) {
        $values[$match[1]] = $match[2];
    }
}

var_dump($values);

Try this

$values = array();

foreach (explode("\n", $text) as $line) {
    if (preg_match('/([^:]++):[^\s]*+(.*+)/', $line, $match)) {
        $values[$match[1]] = $match[2];
    }
}

var_dump($values);

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~没有更多了~