对于 Ruby on Rails，当从 API 获取数据时如何使用 will_paginate 或 Kaminari？（通过网络）

发布于 2024-10-28 08:19:45 字数 238 浏览 7 评论 0原文

看起来 will_paginate 和 Kaminari 都与 ActiveRecord 紧密相关？如果通过API获取数据，那么

http://www.foo.com/fetch_data?type=products&offset=100&count=20

如何使用will_paginate或Kaminari来进行分页呢？如果不能，是否有其他分页解决方案可以在这种情况下工作？

原文

It seems like will_paginate and Kaminari are both very tied into ActiveRecord? If the data is obtained through an API, such as

http://www.foo.com/fetch_data?type=products&offset=100&count=20

then how can you use will_paginate or Kaminari to do the pagination? If cannot, is there other pagination solution that can work in this situation?

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贪恋 2024-11-04 08:19:45

我已经为我的acts_as_indexed 插件在非AR 集上进行了分页。

在您的情况下，它的工作方式如下：

def fetch(page=1, per_page=10)
  total_entries = 1000 # Or whatever method you choose to find the total entries.

  returning ::WillPaginate::Collection.new(page, per_page, total_entries) do |pager|
    url = "http://www.foo.com/fetch_data?type=products&offset=#{pager.offset}&count=#{pager.per_page}"

    results = fetch_example(url)# fetch the actual data here.

    pager.replace results
  end
end

控制器：

def index
  @records = fetch(params[:page])
end

视图：

<%= will_paginate @records %>

填写您自己的方法来获取和处理数据，并计算出总条目。

I already do pagination on a non-AR set for my acts_as_indexed plugin.

In your case it would work something like the following:

def fetch(page=1, per_page=10)
  total_entries = 1000 # Or whatever method you choose to find the total entries.

  returning ::WillPaginate::Collection.new(page, per_page, total_entries) do |pager|
    url = "http://www.foo.com/fetch_data?type=products&offset=#{pager.offset}&count=#{pager.per_page}"

    results = fetch_example(url)# fetch the actual data here.

    pager.replace results
  end
end

Controller:

def index
  @records = fetch(params[:page])
end

Views:

<%= will_paginate @records %>

Fill in your own methods for fetching and processing the data, and working out the total entries.

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忆伤 2024-11-04 08:19:45

我编写了自己的函数来对对象数组进行分页。您可以修改代码以满足您自己的需要：

def array_paginate page, per_page, array
  page = page.to_i
  per_page = per_page.to_i
  total_entries = array.count

  total_pages = (total_entries / per_page.to_f).ceil
  data = format_records( array[ (page-1)*per_page..page*per_page-1] )

  {
    page: page,
    total_pages: total_pages,
    data: data,
  }
end

I wrote my own function to paginate an array of objects. You can modify the code to suit your own needs:

def array_paginate page, per_page, array
  page = page.to_i
  per_page = per_page.to_i
  total_entries = array.count

  total_pages = (total_entries / per_page.to_f).ceil
  data = format_records( array[ (page-1)*per_page..page*per_page-1] )

  {
    page: page,
    total_pages: total_pages,
    data: data,
  }
end

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