如何在Python中读取子进程标准输出的第一个字节,然后丢弃其余部分?
我想读取子进程的标准输出的第一个字节来知道它已经开始运行。之后我想丢弃所有进一步的输出,这样我就不必担心缓冲区。
最好的方法是什么?
说明:我希望子进程继续与我的程序一起运行,我不想等待它终止或类似的事情。理想情况下,应该有一些简单的方法来做到这一点,而无需诉诸线程、分叉或多处理。
如果我忽略输出流或 .close()
它,如果发送的数据多于其缓冲区所能容纳的数据,则会导致错误。
I'd like to read the first byte of a subprocess' stdout to know that it has started running. After that I'd like to discard all further output, so that I don't have to worry about the buffer.
What is the best way to do this?
Clarification: I'd like the subprocess to continue running alongside my program, I don't want to wait for it to terminate or anything like that. Ideally there would be some simple way to do this, without resorting to threading
, fork
ing or multiprocessing
.
If I ignore the output stream, or .close()
it, it causes errors if it is sent more data than it can fit in its buffer.
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如果您使用的是 Python 3.3+,则可以使用
stdout
和stderr
的DEVNULL
特殊值来丢弃子进程输出。或者,如果您使用的是 Python 2.4+,则可以使用以下命令进行模拟:
但是,这不会让您有机会读取 stdout 的第一个字节。
If you're using Python 3.3+, you can use the
DEVNULL
special value forstdout
andstderr
to discard subprocess output.Or if you're using Python 2.4+, you can simulate this with:
However this doesn't give you the opportunity to read the first byte of stdout.
这似乎可行,但感觉不惯用。
示例/测试用法
This seems to work, but it doesn't feel idiomatic.
Example/test usage