显示来自 php json_encode 的 json 数据？
我有这个 jquery 代码，它填充一个输入选择器，它应该显示如下：
$("#demo-input-pre-populated").tokenInput("http://shell.loopj.com/", {
prePopulate: [
{id: 123, name: "Slurms MacKenzie"},
{id: 555, name: "Bob Hoskins"},
{id: 9000, name: "Kriss Akabusi"}
]
});
当我尝试使用 php 从数据库中获取值时，如下所示：
prePopulate: [
<?
$responses = array();
$topicJSON=getQtopics($getQ);
while($row = mysql_fetch_array($topicJSON)){
$response = array(
'id' => $row['id'],
'name' => $row['name']
);
$responses[] = $response;
}
echo json_encode($responses);
?>
],
它显示这样的 json 数据：
prePopulate: [
[{"id":"1","name":"Dormitree"},
{"id":"1482","name":"carriage of goods"}]
],
但在 #demo-input- pre-populated" 输入我未定义，我认为它是因为 php 没有正确地回显 json，我该如何解决这个问题，谢谢:))
i have this jquery code which poplautes a input selector, which should display like this:
$("#demo-input-pre-populated").tokenInput("http://shell.loopj.com/", {
prePopulate: [
{id: 123, name: "Slurms MacKenzie"},
{id: 555, name: "Bob Hoskins"},
{id: 9000, name: "Kriss Akabusi"}
]
});
when i try get the vales from the database using php like this:
prePopulate: [
<?
$responses = array();
$topicJSON=getQtopics($getQ);
while($row = mysql_fetch_array($topicJSON)){
$response = array(
'id' => $row['id'],
'name' => $row['name']
);
$responses[] = $response;
}
echo json_encode($responses);
?>
],
which displays the json data like this:
prePopulate: [
[{"id":"1","name":"Dormitree"},
{"id":"1482","name":"carriage of goods"}]
],
but on the #demo-input-pre-populated" input i get undefined, and i think its becuase php is not echoing the json propelrly, how can i fix this thanks :))
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如果你查看两个 JS 输出，唯一的区别是，在从 PHP 输出的情况下，你有两个额外的方括号
[]- 所以你正在创建一个 JSON 数组的数组在这种情况下，您所需要的只是一个 JSON 对象数组。去掉
prePopulate的封闭[]，因为json_encode已经为您执行此操作：If you look the two JS outputs, the only difference is that you have two extra enclosing square-brackets
[]in the case where you output from PHP - so you're making an array of array of JSON objects in that case while all you need is an array of JSON objects.Get rid of the enclosing
[]forprePopulatebecausejson_encodeis already doing that for you:您的 prePopulate 变量是一个包含对象数组的数组，但您只想它是一个对象数组。
您可以去掉 PHP 块之前和之后的 [ 和 ] 括号，或者在 PHP 块中回显此内容：
array_pop(json_decode($responses))Your prePopulate variable is an array containing an array of objects, but you just want it to be an array of objects.
You can either take off the [ and ] brackets before and after the PHP block, or echo this in your PHP block:
array_pop(json_decode($responses))