如何编写一个允许使用 __name__ 内省实例的类？
编写一个 Foo 类，允许其实例返回使用 __name__ 创建的名称，
A = Foo(args)
str(A.__name__)
应该返回“A”
Writing a class Foo which allows its instances to return the names they were created with using __name__,
A = Foo(args)
str(A.__name__)
should return 'A'
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这是不可能的（至少，并非在所有情况下，并且并非没有肮脏的伎俩）。在您的示例中，
A是对Foo类型的对象的引用。该对象不知道对其的引用是如何存储的。如果你这样写：那么
A和B都引用同一个对象，并且完全无法区分，因此你无法找到哪个对象用于保存对目的。当然，您可以扫描globals()来查找对该对象的引用，然后您会找到A和B。但是，如果del A，A的所有痕迹都会消失。你想做什么？如果您解释了用例，也许我们可以建议您所要求的替代解决方案。
That's not possible (at least, not in all cases and not without dirty tricks). In your example,
Ais a reference to an object of typeFoo. The object has no knowledge of how references to it are stored. If you write:then
AandBboth reference the same object, and are totally indistinguishable, so you couldn't find which one was used to hold the first reference to the object. Of course, you could scanglobals()for references to the object, and you would then findAandB. However, if youdel A, all traces ofAwill have vanished.What are you trying to do? If you explained the use case, maybe we could suggest an alternative solution than what you asked.