捕获虚拟屏幕（所有显示器）
我正在尝试获取整个虚拟屏幕的屏幕截图。这意味着，不仅是主屏幕的图像，还包括连接到计算机的每个屏幕的图像。
有办法做到这一点吗？我尝试使用这个，但它不起作用：
Bitmap b = new Bitmap(SystemInformation.VirtualScreen.Width, SystemInformation.VirtualScreen.Height);
Graphics g = Graphics.FromImage(b);
this.Size = new Size(SystemInformation.VirtualScreen.Width, SystemInformation.VirtualScreen.Height);
g.CopyFromScreen(0, 0, 0, 0, b.Size);
I am trying to get a screenshot of the whole virtual screen. This means, an image of not just the primary screen, but every screen connected to the computer.
Is there a way to do that? I tried using this, but it didn't work:
Bitmap b = new Bitmap(SystemInformation.VirtualScreen.Width, SystemInformation.VirtualScreen.Height);
Graphics g = Graphics.FromImage(b);
this.Size = new Size(SystemInformation.VirtualScreen.Width, SystemInformation.VirtualScreen.Height);
g.CopyFromScreen(0, 0, 0, 0, b.Size);
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文档说：
图形。 CopyFromScreen(Int32, Int32, Int32, Int32, Size)：执行颜色数据的位块传输，对应于像素的矩形，从屏幕到绘图表面但虚拟屏幕不一定是矩形：想象两个分辨率分别为 1920x1200 和 1280x1024 的显示器。因此您需要做的是像您一样创建一个位图，然后枚举您的显示器并执行 CopyFromScreen()< 为编辑： 例如，如果您有两台显示器，分辨率为 1280x1024 的显示器位于 1920x1200 显示器的左侧，则坐标 前者的值为 (-1280,0) - (0, 1024)，因此您需要执行 memoryGraphics.CopyFromScreen(-1280, 0, 0, 0, s); ，其中 s 是
Size(1280,1024)对于第二个，您需要调用memoryGraphics.CopyFromScreen(0, 0, *1280*, 0, s); ， s 将为尺寸(1920, 1200)。希望这有帮助。
The documentation says:
Graphics.CopyFromScreen(Int32, Int32, Int32, Int32, Size): Performs a bit-block transfer of the color data, corresponding to a rectangle of pixels, from the screen to the drawing surface of the Graphics." But the virtual screen is not necessarily a rectangle: imagine two monitors with 1920x1200 and 1280x1024 resolutions. So what you need to do is create a bitmap like you do, then enumerate your monitors and executeCopyFromScreen()for each of them.Edit: If, for instance, you have two monitors, the one having 1280x1024 resolution standing on the left of 1920x1200 one, then the coordinates of the former would be (-1280,0) - (0, 1024). Therefore you need to execute
memoryGraphics.CopyFromScreen(-1280, 0, 0, 0, s);where s is theSize(1280,1024). For the second one you need to callmemoryGraphics.CopyFromScreen(0, 0, *1280*, 0, s);and s would be theSize(1920, 1200).Hope this helps.
就像伊戈尔和汉斯所说，你必须指出源坐标：
Like Igor and Hans have said, you have to indicate the source coordinate :
Igor 是对的，为 SourceX/Y 参数传递 0, 0 是不正确的。迭代 Screen.AllScreens 属性中的 Screen 实例以查找边界矩形。请注意，
CopyFromScreen()有一个错误，它无法捕获分层窗口（设置了TransparencyKey或Opacity的窗口）。检查我的答案 此线程 的解决方法。请注意，捕获整个桌面并不总是可行的，当屏幕未排列成完美的矩形时，您会看到很多黑色，并且
OutOfMemory异常在 32 位计算机上并不罕见。高分辨率显示器。Igor is right, passing 0, 0 for the SourceX/Y arguments isn't correct. Iterate the Screen instances in the
Screen.AllScreensproperty to find the bounding rectangle. Beware thatCopyFromScreen()has a bug, it cannot capture layered windows (the kind that hasTransparencyKeyorOpacityset). Check my answer in this thread for a workaround.Beware that capturing the entire desktop isn't always practical, you'll get lots of black when the screens are not arranged in a perfect rectangle and an
OutOfMemoryexception is not uncommon on a 32-bit machine with high resolution displays.