静态数据成员在 C++ 中是否可以输入其容器类型？

发布于 2024-10-27 19:12:37 字数 422 浏览 0 评论 0原文

我在 C# 或其他语言中使用过类似的东西。

// C#, but I can't remember correctly. Just assume like a pseudo code.
class A
{
    public int b;
    public A(int newB)
    {
        b = newB
    }
    public static const A a1 = A(1);
    public static const A a2 = A(2);
    public static const A a3 = A(3);
}

C++ 中有类似的东西吗？或者有什么推荐的方法来做到这一点？我这样做只是为了在其类名中组织 a1、a2、a3。

原文

I was used something like this in C# or other languages.

// C#, but I can't remember correctly. Just assume like a pseudo code.
class A
{
    public int b;
    public A(int newB)
    {
        b = newB
    }
    public static const A a1 = A(1);
    public static const A a2 = A(2);
    public static const A a3 = A(3);
}

Is there equivalent of this in C++? Or any recommended way to do this? I do this for just to organize a1, a2, a3 within its class name.

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梦里的微风 2024-11-03 19:12:37

C++ 中有类似的东西吗？

以下 C++ 代码与您的 C# 代码等效：

class A
{
    public:
    int b;
    A(int newB) : b(newB)
    {
    }

    //declaration
    static const A a1;
    static const A a2;
    static const A a3;
};

//definition - necessary!
const A A::a1 = A(1);
const A A::a2 = A(2);
const A A::a3 = A(3);

Is there equivalent of this in C++?

The following C++ code is equivalent to your C# code:

class A
{
    public:
    int b;
    A(int newB) : b(newB)
    {
    }

    //declaration
    static const A a1;
    static const A a2;
    static const A a3;
};

//definition - necessary!
const A A::a1 = A(1);
const A A::a2 = A(2);
const A A::a3 = A(3);

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