Perl 数组作为对象变量

发布于 2024-10-27 17:14:32 字数 166 浏览 1 评论 0原文

如果我有一个如下所示的 Java 类，那么类似的 Perl 表示是什么？

class Temp {
  int my_int;
  int my_array[];

  Temp() {
  }
};

具体来说，我有兴趣知道如何使用数组作为对象变量？

原文

If I had a Java class as below, what is the similar Perl representation for the same?

class Temp {
  int my_int;
  int my_array[];

  Temp() {
  }
};

Specifically, I am interested to know how to use array as an object variable?

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棒棒糖 2024-11-03 17:14:32

简短的答案是：

package Temp;

sub new {
    my $self = bless {
        'my_int' => 0,
        'my_array' => [] # The trick here is to use an array *reference*
                         # hence the square brackets rather than ()
    };
    return $self;
}

对于（很多！）更长的答案，请查看 perlref，perllol 和 perlboot 了解分别是参考文献、列表列表和 OOP 训练营。一旦您掌握了基础知识，请考虑使用 Moose 在 Perl 中获得更高级的 OOP 方法。

The short answer is:

package Temp;

sub new {
    my $self = bless {
        'my_int' => 0,
        'my_array' => [] # The trick here is to use an array *reference*
                         # hence the square brackets rather than ()
    };
    return $self;
}

For the (much!) longer answer, have a look at perlref, perllol, and perlboot for an introduction to references, lists of lists, and a OOP bootcamp, respectively. Once you've got your head around the basics, consider using Moose for a more advanced approach to OOP in Perl.

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红衣飘飘貌似仙 2024-11-03 17:14:32

使用 Moose，该类可以写为：

package Temp;

use Moose;

has 'my_int' => (
    'is'  => 'rw',
    'isa' => 'Int',
);

has 'my_array' => (
    'is'  => 'rw',
    'isa' => 'ArrayRef[Int]',
);

__PACKAGE__->meta->make_immutable();

Using Moose, the class could be written as:

package Temp;

use Moose;

has 'my_int' => (
    'is'  => 'rw',
    'isa' => 'Int',
);

has 'my_array' => (
    'is'  => 'rw',
    'isa' => 'ArrayRef[Int]',
);

__PACKAGE__->meta->make_immutable();

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