简单的上卡西弗无限循环
简单的 upper-casifier 无限循环
我的代码有什么问题吗?
有什么建议吗?
我的编程环境是linux、emacs、汇编、at&t语法
.section .data
.section .bss
.lcomm buffer,1
.section .text
.global _start
_start:
movl %esp,%ebp
subl $8,%esp
#8(%ebp) is 2nd arg == input
#12(%ebp) is 3rd arg == output
#open,read,open,write,close
movl $5,%eax
movl 8(%ebp),%ebx
movl $0,%ecx
movl $0666,%edx
int $0x80
#%eax contains input's fd
#movl to first local var
movl %eax,-4(%ebp)
movl $5,%eax
movl 12(%ebp),%ebx
movl $03101,%ecx
movl $0666,%edx
int $0x80
#eax contains output's fd
#movl to second local var
movl %eax,-8(%ebp)
loop:
#read 1 byte from file 1st byte of data
movl $3,%eax
movl -4(%ebp),%ebx
movl $buffer,%ecx
movl $1,%edx
int $0x80
#buffer contains 1 byte of file
cmpb $0,buffer
je program_exit
pushl buffer
call convert #will return converted to %al
addl $4,%esp
movb %al,buffer
#write 1 byte from buffer to file
movl $1,%edx
movl $buffer,%ecx
movl -8(%ebp),%ebx
movl $4,%eax
int $0x80
jmp loop
program_exit:
movl buffer,%ebx
movl $1,%eax
int $0x80
.type convert,@function
convert:
pushl %ebp
movl %esp,%ebp
movb 8(%ebp),%al #1 byte data in the buffer
cmpb $'a',%al
jl convert_end
cmpb $'z',%al
jg convert_end
addb $32,%al #convert to upper
convert_end:
movl %ebp,%esp
popl %ebp
ret
simple upper-casifier loop infinitely
what's wrong with my code?
any advice?
my programming environment is linux, emacs, assembly, at&t syntax
.section .data
.section .bss
.lcomm buffer,1
.section .text
.global _start
_start:
movl %esp,%ebp
subl $8,%esp
#8(%ebp) is 2nd arg == input
#12(%ebp) is 3rd arg == output
#open,read,open,write,close
movl $5,%eax
movl 8(%ebp),%ebx
movl $0,%ecx
movl $0666,%edx
int $0x80
#%eax contains input's fd
#movl to first local var
movl %eax,-4(%ebp)
movl $5,%eax
movl 12(%ebp),%ebx
movl $03101,%ecx
movl $0666,%edx
int $0x80
#eax contains output's fd
#movl to second local var
movl %eax,-8(%ebp)
loop:
#read 1 byte from file 1st byte of data
movl $3,%eax
movl -4(%ebp),%ebx
movl $buffer,%ecx
movl $1,%edx
int $0x80
#buffer contains 1 byte of file
cmpb $0,buffer
je program_exit
pushl buffer
call convert #will return converted to %al
addl $4,%esp
movb %al,buffer
#write 1 byte from buffer to file
movl $1,%edx
movl $buffer,%ecx
movl -8(%ebp),%ebx
movl $4,%eax
int $0x80
jmp loop
program_exit:
movl buffer,%ebx
movl $1,%eax
int $0x80
.type convert,@function
convert:
pushl %ebp
movl %esp,%ebp
movb 8(%ebp),%al #1 byte data in the buffer
cmpb
a',%al
jl convert_end
cmpb
z',%al
jg convert_end
addb $32,%al #convert to upper
convert_end:
movl %ebp,%esp
popl %ebp
ret
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(1)
请注意,
read(2)
通过返回0
发出文件结束条件信号。您试图通过查找 asciiNUL
来找到文件的结尾,这在 Unix 派生系统上非常罕见。 (如果您想要一种简单的方法来制作太字节大小的文件,dd if=/dev/zero of=/tmp/huge bs=1048576eek=1048576count=1
。整个事情将是填充 asciiNUL
字符(或者整数0
,但是您想解释它。)您需要修改代码以通过比较来找到文件结尾。
read(2)
系统调用的返回值,而不是通过查看接收到缓冲区的数据。Note that
read(2)
signals an end-of-file condition by returning0
. You're trying to find the end of the file by looking for an asciiNUL
, which is very rare on Unix-derived systems. (If you want an easy way to make a terabyte-sized file,dd if=/dev/zero of=/tmp/huge bs=1048576 seek=1048576 count=1
. The whole thing will be filled with asciiNUL
characters. (Or the integer0
, however you want to interpret it.)You need to modify your code to find the end of file by comparing the return value of the
read(2)
system call, not by looking at the data you receive into your buffer.