组合回收多个自连接的 mysql 查询
我有以下一组 MySQL 查询,用于跟踪用户在网站上的进度。有没有好的方法来简化它们?
#How many people reached stage 2
SELECT COUNT(DISTINCT a.session_id) as "total"
FROM formation_page_hits a
WHERE a.progress = 2
AND DATE(a.datetime) = "2011-03-23";
#How many people reached stage 4 having reached stage 2
SELECT COUNT(DISTINCT a.session_id) as "total"
FROM formation_page_hits a, (SELECT f.session_id, f.`datetime`
FROM formation_page_hits f
WHERE f.progress = 2) as b
WHERE a.progress = 4
AND a.session_id = b.session_id
AND DATE(b.datetime) = "2011-03-23"
AND DATE(a.datetime) = "2011-03-23";
#How many people reached stage 7, having reached stage 4, having reached stage 2
SELECT COUNT(DISTINCT a.session_id) as "total"
FROM formation_page_hits a, (SELECT f.session_id, f.`datetime`
FROM formation_page_hits f
WHERE f.progress = 4) as b, (SELECT f.session_id, f.`datetime`
FROM formation_page_hits f
WHERE f.progress = 2) as c
WHERE a.progress = 7
AND a.session_id = b.session_id
AND a.session_id = c.session_id
AND DATE(c.datetime) = "2011-03-23"
AND DATE(b.datetime) = "2011-03-23"
AND DATE(a.datetime) = "2011-03-23";
正如您所看到的,我非常快速地重新查询相同的信息,并且还有另外 4 或 5 个遵循相同模式的查询 - 是否有更好的方法来构建查询,这意味着我不必继续查询对于“有多少人达到第二阶段”?
编辑:每个页面浏览量都存储为 Formation_page_hits 中的一个条目 - 以便有每个会话的页面浏览量的完整记录
id_formation_page_hits INT PRIMARY_KEY, session_id VARCHAR(100), datetime DATETIME, progress INT
I have the following set of MySQL queries, used to track user progress through a website. Is there a good way to simplify them?
#How many people reached stage 2
SELECT COUNT(DISTINCT a.session_id) as "total"
FROM formation_page_hits a
WHERE a.progress = 2
AND DATE(a.datetime) = "2011-03-23";
#How many people reached stage 4 having reached stage 2
SELECT COUNT(DISTINCT a.session_id) as "total"
FROM formation_page_hits a, (SELECT f.session_id, f.`datetime`
FROM formation_page_hits f
WHERE f.progress = 2) as b
WHERE a.progress = 4
AND a.session_id = b.session_id
AND DATE(b.datetime) = "2011-03-23"
AND DATE(a.datetime) = "2011-03-23";
#How many people reached stage 7, having reached stage 4, having reached stage 2
SELECT COUNT(DISTINCT a.session_id) as "total"
FROM formation_page_hits a, (SELECT f.session_id, f.`datetime`
FROM formation_page_hits f
WHERE f.progress = 4) as b, (SELECT f.session_id, f.`datetime`
FROM formation_page_hits f
WHERE f.progress = 2) as c
WHERE a.progress = 7
AND a.session_id = b.session_id
AND a.session_id = c.session_id
AND DATE(c.datetime) = "2011-03-23"
AND DATE(b.datetime) = "2011-03-23"
AND DATE(a.datetime) = "2011-03-23";
As you can see, I'm very quickly re-querying the same information and there are an additional 4 or 5 queries that follow the same pattern - is there a better way of constructing the query that means I don't have to keep querying for "how many people reached stage 2"?
EDIT: each page view is stored as an entry in formation_page_hits - so that there is a complete record of page views for each session
id_formation_page_hits INT PRIMARY_KEY, session_id VARCHAR(100), datetime DATETIME, progress INT
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在
(session_id,datetime,progress)
上创建一个复合索引,以便快速工作。Create a composite index on
(session_id, datetime, progress)
for this to work fast.