C：在没有 main() 的情况下编译一些对象（对于共享库）失败？

发布于 2024-10-26 15:23:07 字数 730 浏览 2 评论 0原文

据我所知，我需要按照此步骤准备制作共享库：

gcc -fPIC libfoo.c -o libfoo.o

然后链接它。我曾尝试制作一个 makefile 来帮助完成这些步骤，但现在似乎出现了错误。

当我运行 make 文件时会发生这种情况：

foo@box:~/Projects/so$ gcc -fPIC ./libfoo.c -o libfoo.o
/usr/lib/gcc/i686-linux-gnu/4.4.5/../../../../lib/crt1.o: In function `_start':
(.text+0x18): undefined reference to `main'
collect2: ld returned 1 exit status

如何在没有 main 函数的情况下编译库文件，因为它不是程序而是旨在成为库？

如果它对我的程序有帮助，基本上是这样的（解释的）

(stdio and openssl headers here)

(debugging macro definitions here)

(two functions, gettime() and opensslrandom() defined here)

我似乎在理解宏方面也有问题，因为它们最终会在共享库中，它们在共享库中毫无用处？我将它们包含在 libfoo.h 中，尽管我还没有看到这些宏是否有效。

原文

From what I have learned I need to follow this step to prepare for making a shared library:

gcc -fPIC libfoo.c -o libfoo.o

And then I link it. I had tried making a makefile to aid in these steps, but there appears to be errors happening now.

This occurs when I run the make file:

foo@box:~/Projects/so$ gcc -fPIC ./libfoo.c -o libfoo.o
/usr/lib/gcc/i686-linux-gnu/4.4.5/../../../../lib/crt1.o: In function `_start':
(.text+0x18): undefined reference to `main'
collect2: ld returned 1 exit status

How can I compile the library file without the main function, as it is not a program and is intended to be a library?

If it helps my program is basically this (interpreted)

(stdio and openssl headers here)

(debugging macro definitions here)

(two functions, gettime() and opensslrandom() defined here)

I seem to have problems understanding about the macros as well, as they would be in the shared library in the end they are useless in the shared library? I included them in libfoo.h to be included, although I have yet to see if the macros work.

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