如何在python3中的分隔标记处合并两个列表

Question

我是阿拉巴马大学的计算机科学专业学生，我们的 python 课上有一个项目，但我陷入了困境......可能是出于某种愚蠢的原因，但我似乎找不到答案。

这是该项目的链接，因为在这里尝试和解释会很痛苦。

http://beastie.cs.ua.edu/cs150/projects/project1.html

这是我的代码：

import sys
from scanner import scan

def clInput():
    #Gets command line input

    log1 = sys.argv[1]
    log2 = sys.argv[2]
    name = sys.argv[3]

    if len(sys.argv) != 4:
        print('Incorrect number of arguments, should be 3')
        sys.exit(1)
    return log1,log2,name

def openFiles(log1,log2):
    #Opens sys.argv[1]&[2] for reading

    f1 = open(log1, 'r')
    f2 = open(log2, 'r')
    return f1, f2


def merge(log1,log2):
    #Merges parsed logs into list without '---'

    log1Parse = [[]]
    log2Parse = [[]]
    log1Count = 0
    log2Count = 0
    for i in log1:
        if i != ['---']:
            log1Parse[log1Count].append(i)
        else:
            log1Count += 1
            log1Parse.append([])

    for i in log2:
        if i != ['---']:
            log2Parse[log2Count].append(i)
        else:
            log2Count += 1
            log2Parse.append([])

return(log1Parse[0] + log2Parse[0] + log1Parse[1] + log2Parse[1])


def searchMerge(name,merged):
    #Searches Merged list for sys.argv[3]

    for i in range(len(merged)):
        if (merged[i][1] == name):
            print(merged[i][0],merged[i][1]," ".join(merged[i][2:]))



def main():
    log1,log2,name = clInput()
    f1,f2 = openFiles(log1,log2)

    #Sets the contents of the two scanned files to variables
    tokens1 = scan(f1)
    tokens2 = scan(f2)

    #Call to merge and search
    merged = merge(tokens1,tokens2)
    searchMerge(name,merged)




main()

好的。所以这就是问题所在。我们要将两个列表合并到一个排序的主列表中，以 --- 分隔，

我的两个日志文件与我上面链接的网站上发布的日志文件相匹配。该代码可以工作，但是如果每个列表中有两个以上的 --- 实例，它将不会跳转到下一个列表以获取其他标记，依此类推。我用合并功能让它可以为两个人工作。在该函数结束时我返回

return(log1Parse[0] + log2Parse[0] + log1Parse[1] + log2Parse[1])

，但这仅适用于 --- 的两个实例。无论如何，我是否可以更改返回以查看所有索引，而不必手动输入 [0]、[1]、[2] 等？我需要它来分隔和合并任意数量。请帮忙！！

ps 忽略新手...我是一个新手，我们都必须从某个地方开始

p.ps - from Scanner import scan 是我编写的一个扫描仪，用于接收给定列表中的所有标记

Answer 1

so.py：

import sys

def main():
    # check and load command line arguments
    # your code
    if len(sys.argv) != 4:
        print('Incorrect number of arguments, should be 3')
        sys.exit(1)

    # open files using file io
    # your code
    f1 = open(log1, 'r')
    f2 = open(log2, 'r')

    # list comprehension to process and filter log files
    l1 = [ x.strip().split(" ",2) for x in f1.readlines() if x.strip() != "---" ]
    l2 = [ x.strip().split(" ",2) for x in f2.readlines() if x.strip() != "---" ]

    f1.close()
    f2.close()

    sorted_merged_lists = sorted(l1 + l2)

    results = [ x for x in sorted_merged_lists if x[1] == name ]

    for result in results:
        print result

main()

CLI：

$ python so.py log1.txt log2.txt Matt
['12:06:12', 'Matt', 'Logged In']
['13:30:07', 'Matt', 'Opened Terminal']
['15:02:00', 'Matt', 'Opened Evolution']
['15:31:16', 'Matt', 'Logged Out']

文档：

http://docs.python.org/ release/3.0.1/tutorial/datastructs.html#list-compressives
http://docs.python.org /release/3.0.1/library/stdtypes.html?highlight=strip#str.strip
http://docs.python.org /release/3.0.1/library/stdtypes.html?highlight=split#str.split
http://docs.python.org/release /3.0.1/library/functions.html?highlight=sorted#sorted