更改页面加载时的所有网址

发布于 2024-10-26 12:30:13 字数 463 浏览 1 评论 0原文

假设我有一个页面，我想在其中向每个 url（还有图像等）附加一个参数（例如 ?name=fc）。

我正在尝试使用正则表达式使用greasemonkey 来执行此操作，但它似乎不起作用（即页面上的链接不会更改）。

这是我的代码

var txt = document.documentElement.innerHTML;
var exp = "/(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/ig" ;
document.documentElement.innerHTML =( txt.replace(exp, "$1?name=fc"));

我的 JavaScript 知识几乎为零，所以请耐心等待。

那么问题来了，JavaScript 出了什么问题？

原文

Let's suppose I have a page in which I'd like to append a parameter (for example ?name=fc) to each and every url (also images etc.).

I'm trying to do this with greasemonkey using a regex, but it doesn't seem to work (i.e., the links on the page don't change).

Here is my code

var txt = document.documentElement.innerHTML;
var exp = "/(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/ig" ;
document.documentElement.innerHTML =( txt.replace(exp, "$1?name=fc"));

My JavaScript knowledge is almost zero, so bear with me.

So the question is, what's wrong with that JavaScript?

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为人所爱 2024-11-02 12:30:13

for(var i = 0; i < document.links.length; i++) {
 document.links[i].href += "?name=fc"
}

您应该只使用 document.links 属性。这会将“?name=fc”附加到所有链接（a 和 img 等）。

for(var i = 0; i < document.links.length; i++) {
 document.links[i].href += "?name=fc"
}

You should just use the document.links attribute. This will append "?name=fc" to all links (a's and img's etc).

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守望孤独 2024-11-02 12:30:13

//loop 1: change links <a href="..."
var links = document.getElementsByTagName('a');
for(var i = 0, len = links.length; i < len; ++i)
   links[i].href = links[i].href + "?name=fc";

//loop 2: change images <img src="..."
var imgs = document.getElementsByTagName('img');
for(var i = 0, len = imgs.length; i < len; ++i)
   imgs[i].href = imgs[i].href + "?name=fc";

//loop 3: change image maps <area href="..."
var areas = document.getElementsByTagName('area');
for(var i = 0, len = areas.length; i < len; ++i)
   areas[i].href = areas[i].href + "?name=fc";

正如 Mike Lewis 在另一个答案中指定的那样循环 1 和 3 您可以使用他的答案编写一个循环，但您仍然需要用于图像的 src 的循环 2

//loop 1: change links <a href="..."
var links = document.getElementsByTagName('a');
for(var i = 0, len = links.length; i < len; ++i)
   links[i].href = links[i].href + "?name=fc";

//loop 2: change images <img src="..."
var imgs = document.getElementsByTagName('img');
for(var i = 0, len = imgs.length; i < len; ++i)
   imgs[i].href = imgs[i].href + "?name=fc";

//loop 3: change image maps <area href="..."
var areas = document.getElementsByTagName('area');
for(var i = 0, len = areas.length; i < len; ++i)
   areas[i].href = areas[i].href + "?name=fc";

As specified by Mike Lewis in the other answer in place of loop 1 and 3 you could write one single loop using his answer, but still you need the loop 2 for images' srcs

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