计算数组数据

Question

我需要有 4 个这样的关联数组，具有相同的 4 个用户，

Array ( [0] => Array ( [userName] => jim [count] => 6 ) [1] => Array ( [userName] => joe [count] => 6 ) [2] => Array ( [userName] => jesse [count] => 36 ) [3] => Array ( [userName] => mark [count] => 2 ) ) 


Array ( [0] => Array ( [userName] => jim [count] => 2 ) [1] => Array ( [userName] => jesse [count] => 2 ) [2] => Array ( [userName] => mark [count] => 16 ) ) 


Array ( [0] => Array ( [userName] => jim [count] => 8 ) ) 


Array ( )

我们可以说他们被命名为

$values1
$values2
$values3
$values4

他们可能拥有所有 4 个用户，他们也可能没有任何或只有一些

我需要合计所有值并拥有一个像这样的

 $people = array(
    array("name" => "jim", "score" => 33), 
    array("name" => "jesse", "score" => 44),
    array("name" => "mark", "score" => 66),
    array("name" => "joe", "score" => 11)
 );

数组一种添加这些值并将这样的一个数组与所有添加的数据相信任的简单方法

我确信我可以通过强力方式找出它，但我想知道是否有一种干净的方法可以做到这一点

Answer 1

最简单的方法是创建具有此结构的数组：

$people = array(
    'jim' => 33,
    'jess' => 44
    // ...
);

可以使用 this 循环创建此数组：

$people = array();

foreach(array_merge($values1, $values2, $values3, $values4) as $person) {
    $name = $person['name'];
    if(!isset($people[$name])) {
        $people[$name] = 0;
    }
    $people[$name] += $person['score'];
}

从此时起，可以直接使用此结构或将其转换为所需的格式。

Answer 2

你可以这样做：

$people = array();

foreach(array_merge($values1, $values2, $values3, $values4) as $k=>$v){
   if(isset($people[$v['username']]){
        $people[$v['username']]['score'] += $v['count'];
   }
   else {
       $people[$v['username']] = array();
       $people[$v['username']]['score'] = $v['count']; 
   }
}

这会给你这样的结果：

$people = array(
    "jim" => array("score" => 33), 
    "jesse" => array("score" => 44),
    "mark" => array("score" => 66),
    "joe" => array("score" => 11)
 );

Answer 3

我认为这就是您希望在 http://www.oriontechnologysolutions.com/stackoverflow 上看到它的实际效果/arraycount.php：

$list1 = Array (Array ( 'userName' => 'jim', 'count' => 6 ),Array ( 'userName' => 'joe' , 'count' => 6 ), Array ( 'userName' => 'jesse', 'count' => 36 ), Array ( 'userName' => 'mark' , 'count' => 2 ) ) ;
$list2 = Array (Array ( 'userName' => 'jim' , 'count' => 2 ), Array ( 'userName' => 'jesse' , 'count' => 2 ), Array ( 'userName' => 'mark' , 'count' => 16 ) ) ;
$list3 = Array (Array ( 'userName' => 'jim', 'count' => 8 ) ) ;
$list4 = Array ( );


$master_list = Array($list1, $list2, $list3, $list4);
$final = Array();
foreach($master_list as $glist) {
        foreach($glist as $person) {
                if(!isset($final[$person['userName']]))
                        $final[$person['userName']] = 0;
                $final[$person['userName']] += $person['count'];
        }
}
print_r($final);

Answer 4

这是第三种替代方案，封装为函数格式。 ;-)

// tally_counts($score1, $scores2[, $score3[, ...]])
function tally_counts(){
  $result = array();
  foreach (func_get_args() as $counts){
    foreach ($counts as $count){
      if (!array_key_exists($count['userName'],$result)){
        $result[$count['userName']] = array(
          'name'  => $count['userName'],
          'count' => $count['count']
        );
      }else{
        $result[$count['userName']]['count'] += $count['count'];
      }
    }
  }
  return array_values($result);
}

演示