IMAP COPY 命令 - uid 和 Message-Id
我知道 UID 会发生变化，但在对特定邮件进行任何操作期间，Message-Id 不会更改。然而，经过一些操作后，我想到了这种情况：
假设我的 INBOX 中有 总共 2000 封电子邮件。如果我将带有 UID 1000 和 Message-Id 1000 的第 1000 封电子邮件复制到我的 Trash 邮箱，然后复制返回INBOX，UID 将更改为 2000，Message-Id 将更改为 2000；该文件夹的当前值。然后，无论日期如何，该电子邮件都会位于顶部。
现在的问题是，如果我 .快速获取 1990:2000（最后 10 封电子邮件），我将在获取的 10 封电子邮件中获取该特定电子邮件。如何根据日期获取最后 10 封电子邮件，而不必获取 2000 封电子邮件，然后按日期对它们进行排序？
I understood that UID changes but the Message-Id will not be changed during any operation on a particular mail. However, after some operations I came up with this case:
Lets assume I have a total of 2000 emails in my INBOX. If I copy the 1000th email with UID 1000 and Message-Id 1000 to my Trash mailbox and then I copy that back to the INBOX, the UID will change to 2000 and Message-Id to 2000; the current for that folder. Then, regardless of the date that email will be at the top.
Now the question is, if I . fetch 1990:2000 fast (the last 10 emails), I'll get the that particular email among the 10 fetched. How would you fetch the last 10 based on the date without having to fetch 2000 emails and then sort them out by date?
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如果 IMAP 服务器支持，您可以使用 SORT 命令，如 RFC 5256 中所述。您正在寻找的特定命令可能是：
服务器响应是可用于后续提取的消息序列号列表。
如果您的服务器支持
SORT扩展（现代IMAP服务器支持），它将在响应CAPABILITY命令时宣布。以下是我正在运行的旧版 Courier-IMAP 的响应：If the IMAP server supports it, you can use the SORT command for this, as descibed in RFC 5256. The specific command you're looking for is probably:
The server response is a list of message sequence numbers that you can use for a subsequent fetch.
If your server supports the
SORTextension (modern IMAP servers do), it will be announced in response to theCAPABILITYcommand. Here's a response from the ancient version of Courier-IMAP I'm running: