如何使用 C# 发送/接收 SOAP 请求和响应?

发布于 2024-10-25 21:43:43 字数 2983 浏览 5 评论 0原文

private static string WebServiceCall(string methodName)        
{
    WebRequest webRequest = WebRequest.Create("http://localhost/AccountSvc/DataInquiry.asmx");
    HttpWebRequest httpRequest = (HttpWebRequest)webRequest;             
    httpRequest.Method = "POST";             
    httpRequest.ContentType = "text/xml; charset=utf-8";
    httpRequest.Headers.Add("SOAPAction: http://tempuri.org/" + methodName);
    httpRequest.ProtocolVersion = HttpVersion.Version11;
    httpRequest.Credentials = CredentialCache.DefaultCredentials;
    Stream requestStream = httpRequest.GetRequestStream();              
    //Create Stream and Complete Request             
    StreamWriter streamWriter = new StreamWriter(requestStream, Encoding.ASCII);

    StringBuilder soapRequest = new StringBuilder("<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\"");
    soapRequest.Append(" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" ");
    soapRequest.Append("xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\"><soap:Body>");
    soapRequest.Append("<GetMyName xmlns=\"http://tempuri.org/\"><name>Sam</name></GetMyName>");
    soapRequest.Append("</soap:Body></soap:Envelope>");

    streamWriter.Write(soapRequest.ToString());             
    streamWriter.Close();              
    //Get the Response    
    HttpWebResponse wr = (HttpWebResponse)httpRequest.GetResponse();
    StreamReader srd = new StreamReader(wr.GetResponseStream()); 
    string resulXmlFromWebService = srd.ReadToEnd(); 
    return resulXmlFromWebService;
}

我尝试了不同的代码来发送/接收肥皂响应,但都失败并显示相同的“远程服务器返回错误:(500)内部服务器错误。”

我可以使用 SoapUI 访问相同的服务。我也能够调用该方法。我在这个论坛上读到,我收到 500 错误的原因可能是错误的标头。我验证了标题,似乎没问题。如果有人可以提供帮助,我将不胜感激。

以下是示例 SOAP 请求:

POST /AccountSvc/DataInquiry.asmx HTTP/1.1
Host: abc.def.gh.com
Content-Type: text/xml; charset=utf-8
Content-Length: length
SOAPAction: "http://tempuri.org/GetMyName"

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
  <soap:Body>
    <GetMyName xmlns="http://tempuri.org/">
      <name>string</name>
    </GetMyName>
  </soap:Body>
</soap:Envelope>

我使用上面的示例请求来执行该方法,并且它有效。以下是我传递的 Soap 请求:

<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"><soap:Body><GetMyName xmlns="http://tempuri.org/"><name>Sam</name></GetMyName></soap:Body></soap:Envelope>

编辑:

我已更新了适用于 .asmx 服务的 WebServiceCall 中的上述代码。但相同的代码不适用于 WCF 服务。为什么?

private static string WebServiceCall(string methodName)        
{
    WebRequest webRequest = WebRequest.Create("http://localhost/AccountSvc/DataInquiry.asmx");
    HttpWebRequest httpRequest = (HttpWebRequest)webRequest;             
    httpRequest.Method = "POST";             
    httpRequest.ContentType = "text/xml; charset=utf-8";
    httpRequest.Headers.Add("SOAPAction: http://tempuri.org/" + methodName);
    httpRequest.ProtocolVersion = HttpVersion.Version11;
    httpRequest.Credentials = CredentialCache.DefaultCredentials;
    Stream requestStream = httpRequest.GetRequestStream();              
    //Create Stream and Complete Request             
    StreamWriter streamWriter = new StreamWriter(requestStream, Encoding.ASCII);

    StringBuilder soapRequest = new StringBuilder("<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\"");
    soapRequest.Append(" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" ");
    soapRequest.Append("xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\"><soap:Body>");
    soapRequest.Append("<GetMyName xmlns=\"http://tempuri.org/\"><name>Sam</name></GetMyName>");
    soapRequest.Append("</soap:Body></soap:Envelope>");

    streamWriter.Write(soapRequest.ToString());             
    streamWriter.Close();              
    //Get the Response    
    HttpWebResponse wr = (HttpWebResponse)httpRequest.GetResponse();
    StreamReader srd = new StreamReader(wr.GetResponseStream()); 
    string resulXmlFromWebService = srd.ReadToEnd(); 
    return resulXmlFromWebService;
}

I tried different code to send/receive soap responses but all fail with the same "The remote server returned an error: (500) Internal Server Error.".

I can access the same service using SoapUI. Am able to invoke the method too. I read in this forum that the reason why am I getting 500 error could be wrong header. I verified the header, it seems to be ok. I would appreciate if someone can help.

Following is the sample SOAP request:

POST /AccountSvc/DataInquiry.asmx HTTP/1.1
Host: abc.def.gh.com
Content-Type: text/xml; charset=utf-8
Content-Length: length
SOAPAction: "http://tempuri.org/GetMyName"

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
  <soap:Body>
    <GetMyName xmlns="http://tempuri.org/">
      <name>string</name>
    </GetMyName>
  </soap:Body>
</soap:Envelope>

I used the above sample request to execute the method and it worked. Here is the Soap request that I passed:

<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"><soap:Body><GetMyName xmlns="http://tempuri.org/"><name>Sam</name></GetMyName></soap:Body></soap:Envelope>

Edit:

I have updated the code above in WebServiceCall that worked for .asmx service. But the same code didn't work for WCF service. Why?

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帅气尐潴 2024-11-01 21:43:43

网址不同。

  • http://localhost/AccountSvc/DataInquiry.asmx

  • /acctinqsvc/portfolioinquiry.asmx

首先解决此问题,就像 Web 服务器无法解析您尝试 POST 的 URL 一样,您甚至不会开始处理请求所描述的操作。

您只需创建针对 ASMX 根 URL 的 WebRequest,即:http://localhost/AccountSvc/DataInquiry.asmx,并在 SOAPAction 标头中指定所需的方法/操作。

SOAPAction 标头值不同。

  • http://localhost/AccountSvc/DataInquiry.asmx/ + methodName

  • http://tempuri.org/GetMyName< /code>

您应该能够通过转到正确的 ASMX URL 并附加 ?wsdl 来确定正确的 SOAPAction

。与您尝试执行的操作相匹配的 标记,该标记似乎是 GetMyName

请求正文中没有包含 SOAP XML 的 XML 声明。

您在 HttpRequest 的 ContentType 中指定了 text/xml,但没有指定字符集。也许这些默认为 us-ascii,但如果您不指定它们,就无法判断!

SoapUI 创建的 XML 包括指定 utf-8 编码的 XML 声明,该声明也与提供给 HTTP 请求的 Content-Type 匹配,即: text/xml; charset=utf-8

希望有帮助!

The urls are different.

  • http://localhost/AccountSvc/DataInquiry.asmx

vs.

  • /acctinqsvc/portfolioinquiry.asmx

Resolve this issue first, as if the web server cannot resolve the URL you are attempting to POST to, you won't even begin to process the actions described by your request.

You should only need to create the WebRequest to the ASMX root URL, ie: http://localhost/AccountSvc/DataInquiry.asmx, and specify the desired method/operation in the SOAPAction header.

The SOAPAction header values are different.

  • http://localhost/AccountSvc/DataInquiry.asmx/ + methodName

vs.

  • http://tempuri.org/GetMyName

You should be able to determine the correct SOAPAction by going to the correct ASMX URL and appending ?wsdl

There should be a <soap:operation> tag underneath the <wsdl:operation> tag that matches the operation you are attempting to execute, which appears to be GetMyName.

There is no XML declaration in the request body that includes your SOAP XML.

You specify text/xml in the ContentType of your HttpRequest and no charset. Perhaps these default to us-ascii, but there's no telling if you aren't specifying them!

The SoapUI created XML includes an XML declaration that specifies an encoding of utf-8, which also matches the Content-Type provided to the HTTP request which is: text/xml; charset=utf-8

Hope that helps!

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