我们可以在gsub中使用关系运算符吗？

发布于 2024-10-25 21:36:27 字数 435 浏览 2 评论 0原文

我需要将 . 字符替换为 。 \n 采用以下字符串格式。但是，限制是，不要仅在以下模式字符串中将 . 字符替换为 .\n 。

"test was done and was negative. Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

我需要以下输出，例如

"test was done and was negative. \n Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

约束是 => “规格重力= 1.015”。

原文

I need to replace the . character with . \n in the following string format. But, the constraint is, don't replace the . character with .\n in following pattern string only.

"test was done and was negative. Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

I need the following output, like

"test was done and was negative. \n Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

The constraint is => "spec. Grav. = 1.015".

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雨轻弹 2024-11-01 21:36:27

str = "test was done and was negative. Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

puts str.sub('. ', ".\n") 

#=> test was done and was negative.
#=> Urine dipstick: ph = 6\n \342\200\242 spec. Grav.  = 1.015

String.sub 仅替换第一个匹配项。

str = "test was done and was negative. Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

puts str.sub('. ', ".\n") 

#=> test was done and was negative.
#=> Urine dipstick: ph = 6\n \342\200\242 spec. Grav.  = 1.015

String.sub only substitutes the first match.

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亢潮 2024-11-01 21:36:27

str.gsub(/\.(?! (Grav| =))/, ".\n")

应该做这项工作。

简要说明

\. 匹配任何 .
(?!) 表示否定前瞻。这意味着它不会与这些括号中找到的任何内容匹配。
(Grav| =) 因此，后跟 Grav 或 = 的点将不会匹配。

str.gsub(/\.(?! (Grav| =))/, ".\n")

should do the job.

Brief explanation

\. matches any .
(?!) denotes a negative look-ahead. That means that it won't match anything found in these brackets.
(Grav| =) hence a dot followed by either Grav or = won't be matched.

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