如何在 Hibernate 中保留递归属性？
我正在努力处理涉及具有相同类类型属性的类的 Hibernate 映射。即（简化）：
public class A {
protected A next = null;
}
我的映射当前看起来像：
<hibernate-mapping package="mypackage">
<class name="A" table="tblA" lazy="false">
<id name="id">
<generator class="native"/>
</id>
<property name="next" type="A" />
</class>
</hibernate-mapping>
但是在 Hibernate 初始化期间，我在线程“main”org.hibernate.MappingException 中遇到异常：无法确定类型：A，表：tblA，列：[ org.hibernate.mapping.Column(next)]。
我的理解是，我正在尝试使用尚未声明的映射（因为我现在正在这样做），并且我可能需要诸如前向声明之类的东西。你有什么想法吗？
谢谢
通努兹
I am struggling with a Hibernate mapping involving a class with a property of the same class type. I.e. (simplified):
public class A {
protected A next = null;
}
My mapping currently looks like:
<hibernate-mapping package="mypackage">
<class name="A" table="tblA" lazy="false">
<id name="id">
<generator class="native"/>
</id>
<property name="next" type="A" />
</class>
</hibernate-mapping>
However during Hibernate initialization I get a Exception in thread "main" org.hibernate.MappingException: Could not determine type for: A, at table: tblA, for columns: [org.hibernate.mapping.Column(next)].
My understanding is that I am trying to use a mapping which hasn't been declared yet (because I am doing it right now) and I would probably need something like a forward declaration, or so. Do you have any idea?
Thank you
Tunnuz
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它是一个引用：
It is a reference:
<Property>is used for primitive types. There is usually no need to declare the type, since it is determined by Hibernate using reflection.