使用 PHP 根据 JSON 数组中的出生日期信息计算一个人的年龄

发布于 2024-10-25 13:16:14 字数 695 浏览 2 评论 0原文

我想知道如何使用 PHP 来计算一个人的年龄，给定一个带有 JSON 数组值的日期字符串：

{  
    "DOB":{ // should I use integers or strings for these values? I'm assuming strings for now.  
        "year": "1970",  
        "month": "01",  
        "day": "01"  
    }  
}

然后我将如何使用 PHP 来计算年龄？
此外，假设所有这些信息都是员工目录之类的一小部分，格式为 { "People":{ "user1":{ label: value },"user2":{ label: value} } }。如何使用 PHP 在 value 的

标签内为 label 创建标签(

labelvalue

) 在 div 内每个用户的无序列表中每个用户？
请告诉我这是否令人困惑；而年龄的计算是我现在最优先考虑的事情。

原文

I was wondering how I could use PHP to calculate one's age given a date string with values from a JSON array:

{  
    "DOB":{ // should I use integers or strings for these values? I'm assuming strings for now.  
        "year": "1970",  
        "month": "01",  
        "day": "01"  
    }  
}

How would I then use PHP to calculate the age?
Additionally, say all of this information is a small part of something like a staff directory, with the format of { "People":{ "user1":{ label: value },"user2":{ label: value} } }. How could I use PHP to create <label> tags for label within <li> tags for value (<li><label>label</label>value</li>) within unordered lists for each user within divs for each user?
Please tell me if this is confusing; and the calculation of the age is my highest priority right now.

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随梦而飞# 2024-11-01 13:16:14

我假设你要使用这个：

http://php.net/manual/ en/function.json-decode.php

将其转换为 php 可以使用的数组。

<?php

$arr = json_decode('{"DOB":{"year": "1970", "month": "01", "day": "01"}}');
$year = $arr->DOB->year;
$month = $arr->DOB->month;
$day = $arr->DOB->day;

$today = date("Y-m-d"); 
$bday = date("Y-m-d",mktime(0, 0, 0, $month, $day, $year));

$today = new DateTime($today);
$bday = new DateTime($bday);
$age = $today->diff($bday)->y;

echo $age;


?>

我相信这应该在 PHP 5.3+ 中工作。

Im assuming you are going to use this:

http://php.net/manual/en/function.json-decode.php

convert it to an array php can use.

<?php

$arr = json_decode('{"DOB":{"year": "1970", "month": "01", "day": "01"}}');
$year = $arr->DOB->year;
$month = $arr->DOB->month;
$day = $arr->DOB->day;

$today = date("Y-m-d"); 
$bday = date("Y-m-d",mktime(0, 0, 0, $month, $day, $year));

$today = new DateTime($today);
$bday = new DateTime($bday);
$age = $today->diff($bday)->y;

echo $age;


?>

This should work in PHP 5.3+ i believe.

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烟沫凡尘 2024-11-01 13:16:14

不确定我是否正确理解了您要对用户执行的操作，因此如果我弄错了，请告诉我：

<?php
    $people = json_decode($data);
?>
<html>
    <head>
        <title>Users List</title>
    </head>
<body>
    <?php foreach ($people as $userName => $userInfo): ?>
    <div>
        <p><?php echo $userName; ?>
        <ul>
        <?php foreach ($userInfo as $label => $value): ?>
            <li><label><?php echo $label; ?></label> <?php echo $value; ?></li>
        <?php endforeach; ?>
        </ul>
    </div>
    <?php endforeach; ?>
</body>
</html>

Not sure if I correctly understood what you're trying to do with the user so let me know if i was mistaken:

<?php
    $people = json_decode($data);
?>
<html>
    <head>
        <title>Users List</title>
    </head>
<body>
    <?php foreach ($people as $userName => $userInfo): ?>
    <div>
        <p><?php echo $userName; ?>
        <ul>
        <?php foreach ($userInfo as $label => $value): ?>
            <li><label><?php echo $label; ?></label> <?php echo $value; ?></li>
        <?php endforeach; ?>
        </ul>
    </div>
    <?php endforeach; ?>
</body>
</html>

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无语# 2024-11-01 13:16:14

像这样的事情：

<?php
$str = '{"DOB":{"year": "1970","month": "01","day": "01"}}';
$obj = json_decode($str);
$obj->DOB->year = intval($obj->DOB->year);
$obj->DOB->month = intval($obj->DOB->month);
$obj->DOB->day = intval($obj->DOB->day);
$yearD  = date("Y") - $obj->DOB->year;
$monthD = date("m") - $obj->DOB->month;
$dayD   = date("d") - $obj->DOB->day;
if ($dayD < 0 || $monthD < 0)
    $yearD--;
echo "<pre>";
echo $yearD;
echo "</pre>";
?>

没有考虑闰年。只要算一下就没有了。闰年，并添加尽可能多的天数。

关于你的第二个问题，你可以访问这个：Convert JSON to HTML Tree

Something like this:

<?php
$str = '{"DOB":{"year": "1970","month": "01","day": "01"}}';
$obj = json_decode($str);
$obj->DOB->year = intval($obj->DOB->year);
$obj->DOB->month = intval($obj->DOB->month);
$obj->DOB->day = intval($obj->DOB->day);
$yearD  = date("Y") - $obj->DOB->year;
$monthD = date("m") - $obj->DOB->month;
$dayD   = date("d") - $obj->DOB->day;
if ($dayD < 0 || $monthD < 0)
    $yearD--;
echo "<pre>";
echo $yearD;
echo "</pre>";
?>

Didnt take leap years into account. Just calculate no. of leap years, and add as many days.

And about your second question, you could visit this: Convert JSON to HTML Tree

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