在 Rails 中初始化多级哈希

发布于 2024-10-25 09:15:41 字数 147 浏览 1 评论 0原文

所以我有一些代码如下所示：

@foo ||= {}
@foo[:bar] ||= {}
@foo[:bar][:baz] ||= {}

我不关心性能，而是关心清洁度。有没有更漂亮的方式或者更好的方式来做到这一点？

原文

So I have some codes look like the following:

@foo ||= {}
@foo[:bar] ||= {}
@foo[:bar][:baz] ||= {}

I am not concerning the performance, but the cleanness. Is there a more beautiful way or better way to do so?

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北音执念 2024-11-01 09:15:41

{:bar => {:baz => {}}}.merge(@foo)

{:bar => {:baz => {}}}.merge(@foo)

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吾家有女初长成 2024-11-01 09:15:41

我认为你所拥有的是一种编写代码的良好、简洁的方式，但下面是我想到的另一种方法来完成同样的事情。如果您希望更详细的话，它仍然可以完成这项工作：

if @foo.nil?
    @foo = { :bar => { :baz => {} } }
else if @foo[:bar].nil?
    @foo[:bar] = { :baz => {} }
else if @foo[:bar][:baz].nil?
    @foo[:bar][:baz] = {}
end

或者

if !@foo
    @foo = { :bar => { :baz => {} } }
else if !@foo[:bar]
    @foo[:bar] = { :baz => {} }
else if !@foo[:bar][:baz]
    @foo[:bar][:baz] = {}
end

I think what you have is a good, terse way of writing the code, but below is another way I thought of to do the same thing. It'll still do the job, if you'd prefer to be more verbose:

if @foo.nil?
    @foo = { :bar => { :baz => {} } }
else if @foo[:bar].nil?
    @foo[:bar] = { :baz => {} }
else if @foo[:bar][:baz].nil?
    @foo[:bar][:baz] = {}
end

if !@foo
    @foo = { :bar => { :baz => {} } }
else if !@foo[:bar]
    @foo[:bar] = { :baz => {} }
else if !@foo[:bar][:baz]
    @foo[:bar][:baz] = {}
end

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~没有更多了~