将换行符添加到列表中

发布于 2024-10-24 22:36:18 字数 786 浏览 3 评论 0原文

我希望我的程序根据输入生成 CSV。（我正在计算特定输入出现的次数，然后我想在 Excel 中读取该输入。）这仅供我自己使用，以帮助我输入数据，因此只有输出的形式很重要。在代码方面，我完全是业余爱好者，所以请原谅我让程序循环的迂回方法。

SC= []
ender= 0
while ender == 0:
     Data = input('type in the letters:')
     if 'x' in Data:
          SC.append (1, )
     else: SC.append (0, )
     A = input('Done?:')    
     if 'done' in A:
         ender = 1
     else:quit
else:SC.append('/n')

print(SC)

这给了我类似 (1, 0, 1, '/n')
我需要的是 (1, 0, 1, /n)

我已经尝试过 SC.append(//n) -这不应该给我“转义”吗' / 我想要？- 它返回指向第一个 /
的语法错误如果我使用 SC.append(/n) 我会得到指向 /
的相同语法错误我也尝试过使用各种形式的原始字符串但无济于事。

尝试在列表末尾添加这些换行符的问题一直让我发疯。我似乎无法让 python 将文字 /n 附加到列表中。任何帮助将不胜感激。

原文

I want my program to make a CSV out of inputs. (I'm tallying the number of times a particular input appears I then want to read that in Excel.) This is just for my own use to help with my data entry, so only the form of the output matters. I'm a total amateur when it comes to code, so pardon my circuitous method for getting the program to loop.

SC= []
ender= 0
while ender == 0:
     Data = input('type in the letters:')
     if 'x' in Data:
          SC.append (1, )
     else: SC.append (0, )
     A = input('Done?:')    
     if 'done' in A:
         ender = 1
     else:quit
else:SC.append('/n')

print(SC)

This gives me something like (1, 0, 1, '/n')
What I need is (1, 0, 1, /n)

I've tried SC.append(//n) -shouldn't this give me the 'escaped' / I want?- It returns a syntax error that points to the first /
If I use SC.append(/n) I get the same syntax error pointing to the /
I've also tried using the various forms of raw strings to no avail.

The problem of trying to add these line breaks at the end of the list has been driving me crazy. I can't seem to get python to append a literal /n to the list. Any help would be much appreciated.

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濫情▎り 2024-10-31 22:36:18

这肯定不是最好的方法。

我只是尝试对您的代码进行一些编辑：

sc = []
while True:
    data = raw_input('type in the letters:')
    if 'x' in data:
        sc.append("1")
    else:
        sc.append("0")
    checkDone = raw_input('Done?:')
    if 'done' in checkDone:
        break
sc.append('\n')
print(sc)
scWithCommas = ",".join(sc)
print(scWithCommas)

可以进行一些改进：

if 'x' in data 检查意味着如果您键入 xerox ，附加 1。如果您输入 peter，则会在列表中附加 0。可以对其进行更改，以便 xerox 附加 1,0,0,0,1，peter 附加 0,0,0,0,0。
检查done可以避免用户的第二次输入并使用第一个输入。

This is surely not the best way to do it.

I've only tried to make few edits on your code:

sc = []
while True:
    data = raw_input('type in the letters:')
    if 'x' in data:
        sc.append("1")
    else:
        sc.append("0")
    checkDone = raw_input('Done?:')
    if 'done' in checkDone:
        break
sc.append('\n')
print(sc)
scWithCommas = ",".join(sc)
print(scWithCommas)

Several improvements can be made:

The if 'x' in data check means that if you type xerox, an 1 is appended. If you type peter, a 0 is appended on the list. It could be altered so xerox appends 1,0,0,0,1 and peter appends 0,0,0,0,0.
check for done could avoid second input from user and use first input instead.