如何使用指向模板类型的指针

发布于 2024-10-24 02:19:08 字数 904 浏览 2 评论 0原文

对于这个问题的初学者性质，我深表歉意。我似乎无法获得指向模板类型的指针来工作。例如，这是一个头文件：

#include "TemplatedClass.h"
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

这似乎不合法。我做错了什么？谢谢！

编辑添加到示例中。

//TemplatedClass.h
template <class T>
class TemplatedClass
{
public:
    TemplatedClass();
    TemplatedClass(T *t);
    TemplatedClass(const TemplatedClass &t);
    ~TemplatedClass();
    T *getNode() const;
    void setNode(T *t);
private:
    T *node;
};

//TemplatedClass.cpp
#include "TemplatedClass.h"
template <class T>
TemplatedClass<T>::TemplatedClass()
{
    node = 0;
};
template <class T>
TemplatedClass<T>::TemplatedClass(T *t)
{
    node = t;
};
template <class T>
TemplatedClass<T>::TemplatedClass(const TemplatedClass &l)
{
// snip
};

原文

I apologize for the beginner nature of this question. I can't seem to get a pointer to a templated type to work. For example, here is a header file:

#include "TemplatedClass.h"
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

This doesn't seem to be legal. What have I done wrong? Thanks!

edit adding to example.

//TemplatedClass.h
template <class T>
class TemplatedClass
{
public:
    TemplatedClass();
    TemplatedClass(T *t);
    TemplatedClass(const TemplatedClass &t);
    ~TemplatedClass();
    T *getNode() const;
    void setNode(T *t);
private:
    T *node;
};

//TemplatedClass.cpp
#include "TemplatedClass.h"
template <class T>
TemplatedClass<T>::TemplatedClass()
{
    node = 0;
};
template <class T>
TemplatedClass<T>::TemplatedClass(T *t)
{
    node = t;
};
template <class T>
TemplatedClass<T>::TemplatedClass(const TemplatedClass &l)
{
// snip
};

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走过海棠暮 2024-10-31 02:19:08

您需要通过包含定义该类的标头来提供 Point 类的定义。例如：

#include "TemplatedClass.h"
#include "Point.h"   // if this header contains the Point's declaration
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

编辑

实际上，由于您的方法需要一个指针，因此您可以只转发声明：

template< typename T > class TemplatedClass;
class Point;
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

但是然后在源（cpp）文件中您需要包含这些标头

You need to provide the definition of the Point class by including a header where that class is defined. For example :

#include "TemplatedClass.h"
#include "Point.h"   // if this header contains the Point's declaration
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

EDIT

Actually, since your method takes a pointer, you can just forward declare :

template< typename T > class TemplatedClass;
class Point;
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

but then in the source (cpp) file you need to include those headers

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