使用采用 Func的方法在对象生成器上
我正在尝试创建一个对象生成器，以便我可以轻松地创建用于单元测试的对象。我想创建一个 With() 方法，这样我就可以传入一个 Func<>它将为我设置正确的属性。
这是我到目前为止所拥有的：
public class EquipmentModelBuilder
{
public EquipmentModel Object { get; set; }
public EquipmentModelBuilder()
{
Object = new EquipmentModel();
}
public EquipmentModelBuilder WithCategory(int categoryId)
{
Object.EquipmentCategoryID = categoryId;
return this;
}
public EquipmentModelBuilder With(Func<EquipmentModel> setter)
{
Object = setter.Invoke();
return this;
}
public EquipmentModel Build()
{
return Object;
}
}
当然，WithCategory() 可以工作，但我不想为每个属性创建所有方法，我希望能够：
EquipmentModelBuilder.With(x => x.Property1 = 1).With(x => x.Property2 = "2").Build()
知道我做错了什么吗？
I am trying to create an Object Builder so I can easily create objects for unit testing. I would like to create a With() method so I can pass in a Func<> and it will set the correct property for me.
Here is what I have so far:
public class EquipmentModelBuilder
{
public EquipmentModel Object { get; set; }
public EquipmentModelBuilder()
{
Object = new EquipmentModel();
}
public EquipmentModelBuilder WithCategory(int categoryId)
{
Object.EquipmentCategoryID = categoryId;
return this;
}
public EquipmentModelBuilder With(Func<EquipmentModel> setter)
{
Object = setter.Invoke();
return this;
}
public EquipmentModel Build()
{
return Object;
}
}
Of course, the WithCategory() works, but I don't want to create all the methods for each property, I would like to be able to:
EquipmentModelBuilder.With(x => x.Property1 = 1).With(x => x.Property2 = "2").Build()
Any idea what I am doing wrong?
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评论（2）
您需要使用
Action作为参数，而不是Func。You need to use an
Action<EquipmentModel>as your argument rather than aFunc<EquipmentModel>.我认为
Func指定了一个返回 EquipmentModel 的函数，因此您需要的是一个Action，它指定一个不返回且接受的函数EquipmentModel 作为参数。I think that
Func<EquipmentModel>is specifying a function that returns an EquipmentModel, so what you would want is anAction<EquipmentModel>which specifies a function with no return that accepts an EquipmentModel as parameter.