array_unique() 不排序

发布于 2024-10-23 22:46:07 字数 1173 浏览 1 评论 0原文

我正在构建一个扩展 include_path 的自动加载器。它需要一个数组,附加explode()d包含路径,删除对当前目录的所有引用,在数组的开头添加一个当前目录,最后用join()将整个目录重新组合在一起以形成一个新的包含路径。下面列出了代码,

<?php
static public function extendIncludePath (array $paths)
{
    // Build a list of the current and new paths
    $pathList   = array_merge (explode (PATH_SEPARATOR, $paths), explode (PATH_SEPARATOR, get_include_path ()));
    // Remove any references to the current directory from the path list
    while ($key = array_search ('.', $pathList))
    {
        unset ($pathList [$key]);
    }
    // Put a current directory reference to the front of the path
    array_unshift ($pathList, '.');
    // Generate the new path list
    $newPath    = implode (PATH_SEPARATOR, $pathList);
    if ($oldPath = set_include_path ($newPath))
    {
        self::$oldPaths []  = $oldPath;
    }
    return ($oldPath);
}
?>

我还想在内爆数组之前对数组使用 array_unique() ,这样如果有人粗心并且多次指定相同的路径,PHP 就不会多次查找同一个位置。但是,我还需要维护数组的排序顺序,因为 include 按照包含路径中定义的顺序在目录中查找。我想首先查看当前目录,然后是搜索目录列表,最后是原始包含路径,这样,例如,默认 include_path 中的公共库的旧版本不会包含在较新版本中在我的搜索列表中。

由于这些原因,我无法使用 array_unique() 因为它对数组的内容进行排序。

有没有办法让 array_unique 保留数组中元素的顺序?

I'm building an autoloader that extends the include_path. It takes an array, appends the explode()d include path, removes all references to the current directory, adds a single current directory at the start of the array, and finally join() the whole thing back together to form a new include path. The code is listed below

<?php
static public function extendIncludePath (array $paths)
{
    // Build a list of the current and new paths
    $pathList   = array_merge (explode (PATH_SEPARATOR, $paths), explode (PATH_SEPARATOR, get_include_path ()));
    // Remove any references to the current directory from the path list
    while ($key = array_search ('.', $pathList))
    {
        unset ($pathList [$key]);
    }
    // Put a current directory reference to the front of the path
    array_unshift ($pathList, '.');
    // Generate the new path list
    $newPath    = implode (PATH_SEPARATOR, $pathList);
    if ($oldPath = set_include_path ($newPath))
    {
        self::$oldPaths []  = $oldPath;
    }
    return ($oldPath);
}
?>

I wanted to also use array_unique() on the array before imploding it so that PHP doesn't keep looking in the same place multiple times if someone is careless and specifies the same path more than once. However, I also need to maintain the sort order of the array because include looks in the directories in the order they're defined in the include path. I want to look in the current directory first, then my list of search directories and finally the original include path so that, for example, an old version of a common library in the default include_path doesn't get included in favour of a newer version in my search list.

For these reasons I can't use array_unique() because it sorts the array's contents.

Is there a way of getting array_unique to preserve the order of the elements in my array?

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评论(3

屌丝范 2024-10-30 22:46:07

不直接使用array_unique();但 array_unique 确实保留了键,因此您可以随后执行 ksort() 来重新创建条目的原始顺序

Not using array_unique() directly; but array_unique does preserve the keys, so you can do a ksort() afterwards to recreate the original order of entries

じее 2024-10-30 22:46:07

您也可以使用 array_count_value。您将在函数结果的关键处获得唯一的数组结果,

它不会破坏数组排序内容。

参考: http://php.net/manual/en/function.array -count-values.php

you may also use array_count_value. you will get your unique array result at key of your function result

its doesn't break your array sort content.

reference : http://php.net/manual/en/function.array-count-values.php

ゞ花落谁相伴 2024-10-30 22:46:07

像这样的东西:

$temp = array();

foreach ( $original_array as $value ) {
    $temp[$value] = 1;
}

$original_array = array_keys($temp);

Something like:

$temp = array();

foreach ( $original_array as $value ) {
    $temp[$value] = 1;
}

$original_array = array_keys($temp);
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