jqGrid 获取 json 但有空行且没有数据

发布于 2024-10-22 22:23:14 字数 3661 浏览 2 评论 0原文

JSON 由 Spring 3 MVC 生成 @ResponseBody

{
    "total": "1",
    "page": "1",
    "records": "2",
    "rows": [
        {
            "id": "1",
            "cell": {
                "accountId": 1,
                "userId": 1,
                "transactionId": 6,
                "subCatId": 0,
                "accountName": "Credit Card",
                "remarks": "Movie Hall Pass",
                "amount": 250.0,
                "transactionDate": "2011-03-16",
                "subCatName": "Entertainment"
            }
        },
        {
            "id": "2",
            "cell": {
                "accountId": 2,
                "userId": 1,
                "transactionId": 7,
                "subCatId": 1,
                "accountName": "Savings Bank",
                "remarks": "Part at Besand Nagar",
                "amount": 5000.0,
                "transactionDate": "2011-03-16",
                "subCatName": "Dine Out"
            }
        }
    ]
}

JQGrid初始化代码:

$("#transactionLogTable").jqGrid({
                url: '/et/transaction/getTransactions?dateValue=03%2F16%2F2011',
                datatype: "json",
                loadError: function(xhr,status,error){alert(status+" "+error);},
                colNames:['Transaction ID', 'User ID', 'Subcat ID', 'Subcat Name',
                          'Account ID', 'Account Name', 'Date', 'Amount', 'Notes'],

                colModel:[
                    {name: 'transactionId', index: 'transactionId', width: 100},
                    {name: 'userid', index: 'userId', width: 100},
                    {name: 'subCatId', index: 'subCatId', width: 100},
                    {name: 'subCatName', index: 'subCatName', width: 100},
                    {name: 'accountId', index: 'accountId', width: 100},
                    {name: 'accountName', index: 'accountName', width: 100},
                    {name: 'transactionDate', index: 'transactionDate', width: 100},
                    {name: 'amount', index: 'amount', width: 100},
                    {name: 'remarks', index: 'remarks', width: 100}
                ],
                pager: "#pager",
                rowNum: 10,
                rowList: [10,20,30],
                sortname: 'userId',
                sortorder: 'asc',
                viewrecords: true,
                caption: 'Transactions'
            });

使用 QueryString 成功命中服务器,如下所示:

dateValue=03%2F16%2F2011&_search=false&nd=1300532086871&rows=10&page=1&sidx=userId&sord=asc

现在好了,我得到一个屏幕,其中显示了 jqGrid 和 2 个空行。我无法显示行内的数据。

我猜这与映射有关,但我已经尝试了尽可能多的组合。

包含的文件和版本:

<script type="text/javascript" language="javascript" src="/et/resources/js/jquery.jqGrid-3.8.2.full/js/jquery-1.4.2.min.js"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/jquery-ui-1.8.10.start/js/jquery-ui-1.8.10.custom.min.js"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/form-2.52.js"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/validate-1.7.js"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/jquery.jqGrid-3.8.2.full/js/i18n/grid.locale-en.js" charset="utf-8"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/jquery.jqGrid-3.8.2.full/js/jquery.jqGrid.min.js"></script>

感谢您的帮助。

菲尔杜斯·阿米尔

JSON As generated by Spring 3 MVC
@ResponseBody

{
    "total": "1",
    "page": "1",
    "records": "2",
    "rows": [
        {
            "id": "1",
            "cell": {
                "accountId": 1,
                "userId": 1,
                "transactionId": 6,
                "subCatId": 0,
                "accountName": "Credit Card",
                "remarks": "Movie Hall Pass",
                "amount": 250.0,
                "transactionDate": "2011-03-16",
                "subCatName": "Entertainment"
            }
        },
        {
            "id": "2",
            "cell": {
                "accountId": 2,
                "userId": 1,
                "transactionId": 7,
                "subCatId": 1,
                "accountName": "Savings Bank",
                "remarks": "Part at Besand Nagar",
                "amount": 5000.0,
                "transactionDate": "2011-03-16",
                "subCatName": "Dine Out"
            }
        }
    ]
}

JQGrid Initialization Code:

$("#transactionLogTable").jqGrid({
                url: '/et/transaction/getTransactions?dateValue=03%2F16%2F2011',
                datatype: "json",
                loadError: function(xhr,status,error){alert(status+" "+error);},
                colNames:['Transaction ID', 'User ID', 'Subcat ID', 'Subcat Name',
                          'Account ID', 'Account Name', 'Date', 'Amount', 'Notes'],

                colModel:[
                    {name: 'transactionId', index: 'transactionId', width: 100},
                    {name: 'userid', index: 'userId', width: 100},
                    {name: 'subCatId', index: 'subCatId', width: 100},
                    {name: 'subCatName', index: 'subCatName', width: 100},
                    {name: 'accountId', index: 'accountId', width: 100},
                    {name: 'accountName', index: 'accountName', width: 100},
                    {name: 'transactionDate', index: 'transactionDate', width: 100},
                    {name: 'amount', index: 'amount', width: 100},
                    {name: 'remarks', index: 'remarks', width: 100}
                ],
                pager: "#pager",
                rowNum: 10,
                rowList: [10,20,30],
                sortname: 'userId',
                sortorder: 'asc',
                viewrecords: true,
                caption: 'Transactions'
            });

The server is been hit successfully with QueryString as:

dateValue=03%2F16%2F2011&_search=false&nd=1300532086871&rows=10&page=1&sidx=userId&sord=asc

Fine now, I get a screen which has the jqGrid displayed and 2 empty rows in it. I can't get to display the data inside the rows.

I guess it's something related to the mapping, but I have tried as many combinations I can.

Included files and versions:

<script type="text/javascript" language="javascript" src="/et/resources/js/jquery.jqGrid-3.8.2.full/js/jquery-1.4.2.min.js"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/jquery-ui-1.8.10.start/js/jquery-ui-1.8.10.custom.min.js"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/form-2.52.js"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/validate-1.7.js"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/jquery.jqGrid-3.8.2.full/js/i18n/grid.locale-en.js" charset="utf-8"></script>
<script type="text/javascript" language="javascript" src="/et/resources/js/jquery.jqGrid-3.8.2.full/js/jquery.jqGrid.min.js"></script>

Appreciate your help.

Firdous Amir

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评论(1

千里故人稀 2024-10-29 22:23:14

您的主要错误是数据格式错误。你应该使用

{
    "total": "1",
    "page": "1",
    "records": "2",
    "rows": [
        {
            "id": "1",
            "cell": ["1", "1", "6", "0", "Credit Card", "Movie Hall Pass",
                     "250.0", "2011-03-16", "Entertainment" ]
        },
        ...
    ]
}

而不是

{
    "total": "1",
    "page": "1",
    "records": "2",
    "rows": [
        {
            "id": "1",
            "cell": {
                "accountId": 1,
                "userId": 1,
                "transactionId": 6,
                "subCatId": 0,
                "accountName": "Credit Card",
                "remarks": "Movie Hall Pass",
                "amount": 250.0,
                "transactionDate": "2011-03-16",
                "subCatName": "Entertainment"
            }
        },
        ...
    ]
}

一般情况下 jqGrid 足够灵活,可以读取几乎任何 JSON 数据。您只需定义 jsonReader jqGrid 参数,有时还可以定义 jsonmap< /code> 列定义中的属性。例如,在您的情况下,可以使用以下 jqGrid 定义读取您的数据

$("#transactionLogTable").jqGrid({
    // ... other parameters
    cmTemplate: {width: 100},
    colModel:[
        {name:'transactionId',   jsonmap: 'cell.transactionId'},
        {name:'userId',          jsonmap: 'cell.userId'},
        {name:'subCatId',        jsonmap: 'cell.subCatId'},
        {name:'subCatName',      jsonmap: 'cell.subCatName'},
        {name:'accountId',       jsonmap: 'cell.accountId'},
        {name:'accountName',     jsonmap: 'cell.accountName'},
        {name:'transactionDate', jsonmap: 'cell.transactionDate'},
        {name:'amount',          jsonmap: 'cell.amount'},
        {name:'remarks',         jsonmap: 'cell.remarks'}
    ],
    height: "auto",
    jsonReader: { repeatitems: false }
});

这里我使用 jsonReader: { Repeatitems: false } 来定义一行的 JSON 数据不在数组中,而是在 for of 中具有命名属性的对象。需要像 jsonmap: "cell.userId" 这样的属性来指定相应网格列的值不应作为 row 对象的默认 userId 属性,而是另外,它们也是“cell”属性的子属性。顺便说一句,您在 JSON 数据中使用“userid”作为列名称和“userId”。最好使用与 JSON 数据相同的名称。当您使用与“名称”相同的“索引”属性时,您可以删除“索引”。在这种情况下,“名称”属性的值将用作“索引”。

因为您对网格的所有列使用了“width:100”属性,所以我使用了 cmTemplate: {width: 100} 参数来使 colModel 定义更短、更易于阅读。

您可以在此处实时查看修改后的网格。

我建议您另外以 ISO 形式 YYYY-mm-dd 发布日期并使用 格式化程序:'date'colModeldatefmt 属性code> (例如 formatter:'date', formatoptions:{newformat:'dmY'}, datefmt: 'dmY'

Your main error is that the data are wrong formatted. You should use

{
    "total": "1",
    "page": "1",
    "records": "2",
    "rows": [
        {
            "id": "1",
            "cell": ["1", "1", "6", "0", "Credit Card", "Movie Hall Pass",
                     "250.0", "2011-03-16", "Entertainment" ]
        },
        ...
    ]
}

instead of

{
    "total": "1",
    "page": "1",
    "records": "2",
    "rows": [
        {
            "id": "1",
            "cell": {
                "accountId": 1,
                "userId": 1,
                "transactionId": 6,
                "subCatId": 0,
                "accountName": "Credit Card",
                "remarks": "Movie Hall Pass",
                "amount": 250.0,
                "transactionDate": "2011-03-16",
                "subCatName": "Entertainment"
            }
        },
        ...
    ]
}

In general jqGrid is flexible enough to read almost any JSON data. You can just define the jsonReader jqGrid parameter and sometime additionally jsonmap property in the column definition. In your case for example one can read your data with the following jqGrid definition

$("#transactionLogTable").jqGrid({
    // ... other parameters
    cmTemplate: {width: 100},
    colModel:[
        {name:'transactionId',   jsonmap: 'cell.transactionId'},
        {name:'userId',          jsonmap: 'cell.userId'},
        {name:'subCatId',        jsonmap: 'cell.subCatId'},
        {name:'subCatName',      jsonmap: 'cell.subCatName'},
        {name:'accountId',       jsonmap: 'cell.accountId'},
        {name:'accountName',     jsonmap: 'cell.accountName'},
        {name:'transactionDate', jsonmap: 'cell.transactionDate'},
        {name:'amount',          jsonmap: 'cell.amount'},
        {name:'remarks',         jsonmap: 'cell.remarks'}
    ],
    height: "auto",
    jsonReader: { repeatitems: false }
});

Here I used jsonReader: { repeatitems: false } to define that JSON data for a row are not in array for, but in for of object with named property. The property like jsonmap: "cell.userId" is needed to specify that the value for the corresponding grid column should be not as the default userId property of the row object, but are additionally are the child of the "cell" property. By the way you use 'userid' as the column name and 'userId' in the JSON data. It is better to use the same names as the JSON data. In you use the same 'index' property as the 'name' you can drop out the 'index'. In the case the value of the 'name' property will be used as the 'index'.

Because you used "width:100" property for all columns of your grid I used cmTemplate: {width: 100} parameter to make colModel definition shorter and better to read.

You can see the modified grid live here.

I recommend you additionally post the date always in the ISO form YYYY-mm-dd and use formatter:'date' and datefmt properties of colModel (for example formatter:'date', formatoptions:{newformat:'d-m-Y'}, datefmt: 'd-m-Y')

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