如果字段为空，则回显占位符
我有一个输入，我想在其中放入占位符文本，但仅当它的相应值是空字符串。文本框中应输入的值是从 PHP 数组中回显的，但如果该值为空，则应回显占位符。目前，我有这样的代码：
<?php echo sponsorData('address0') == '' ? 'Address Line 1' : 'Other'; ?>
sponsorData() 只是从数组中获取内容；唯一的论点是关键。这里重要的一点是它返回一个字符串。
这段代码给出了奇怪的行为；我得到类似 Hello worldAddress Line 1 的内容，其中 Hello world 是用户输入的文本，而 Address Line 1 显然是占位符。奇怪的是，占位符在提交时被存储到数组中。
我的问题是：有人可以对我的三元运算符进行更正吗？或者，如果这不起作用，请告诉我执行内联 if 语句（blegh）？
谢谢
I have an input that I'd like to put a placeholder text in, but only if it's respective value is an empty string. The value that should go in the textbox is echoed from a PHP array, but if this value is empty, the placeholder should be echoed instead. At the moment, I've got this code:
<?php echo sponsorData('address0') == '' ? 'Address Line 1' : 'Other'; ?>
sponsorData() just gets stuff from an array; it's only argument is the key. The important bit here is it returns astring.
This code gives odd behaviour; I get stuff like Hello worldAddress Line 1, where Hello world is the user typed text and Address Line 1 is obviously the placeholder. Strangely, the placeholder gets stored into the array on submission.
My question is this: can someone offer a correction of my ternary operator or, if that won't work, tell me to do an inline if statement (blegh)?
Thanks
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尝试以下代码：
felix
try the following code:
felix
您遇到了运算符优先级问题。尝试：（
将三元运算符语句放在括号中）。
You're running into operator precedence issues. Try:
(put brackets around the ternary operator statement).
你似乎工作正常，我不认为错误在那里。我将这样做：
You seem to have this working ok, I don't think the error lies there. Here is how I would do it:
您必须考虑到
sponsorData('address0')可能有空格，因此您可以添加trim函数，如下所示：You have to consider that the
sponsorData('address0')may have spaces, so you can add thetrimfunction, like this: