标准 java 类的 .Net 实现
有谁知道 .Net 程序集包含与典型 java 类型具有相同功能的类：
例如，以下内容的 .Net 实现（最好是 C#）包含与 java 类所包含的相同方法。
java.util.HashMap
java.util.LinkedList
等...
我知道 java 集合和 .net 集合之间的一些根本区别，例如在枚举期间删除元素的能力，但这并不意味着大多数功能不能在。网。
提前致谢。
Does anyone know of a .Net assembly that contains classes with the same functionality of the typical java types:
For instance, .Net implementations (preferably c#) of the following that contain the same methods that the java classes contain.
java.util.HashMap
java.util.LinkedList
etc...
I know of some fundamental differences between java collections and .net collections, such as the ability to remove elements during enumeration, but that does not mean that most functions cannot be implemented in .net.
Thanks in advance.
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如果您正在寻找与 Java 兼容的 API 接口，您可能需要查看 IKVM。
If you are looking for API compatible interfaces with Java, you may want to look into IKVM.
System.Collections.Generic和System.Collections保留您要查找的类型，LinkedList和HashTable分别虽然可能有更好的泛型替代品，例如Dictionary取决于您的意图。System.Collections.GenericandSystem.Collectionshold the types you are looking for,LinkedListandHashTablerespecitively although there are probably better alternatives with generics such as aDictionary<TKey, TValue>depending on your intentions.查看 System.Collections 或 System.Collections.Generic 命名空间，这些包含主集合类。
您可能想要查看的另一个有用工具是 IKVM.NET。该框架允许您使用 .NET 中的 Java API 类，并提供一些用于 Java 和 .NET 之间互操作的机制。
Take a look at the System.Collections or System.Collections.Generic namespaces in .NET, these contain the main collection classes.
Another useful tool you might want to check out is IKVM.NET. This framework allows you to use the Java API classes from .NET, and provides some mechanisms for interoperate between Java and .NET.
您是否正在寻找完全相同相同的方法？
我的意思是，
HashMap基本上与Dictionary相同，而LinkedList则 基本上与LinkedList相同。所以就是这样。我不知道有人制造了精确的克隆，只是因为不清楚它的价值是什么。
Are you looking for exactly the same methods?
I mean,
HashMapis basically the same asDictionary<TKey, TValue>, whileLinkedListis basically the same asLinkedList<T>. So there's that.I don't know that anyone's made exact clones just because it's unclear what the value of that would be.