从 EditText 获取文本字符串?
看来我不知道如何从 EditText
中获取文本字符串。 我想在按下按钮时使用 EditText
中的文本。
layout.xml:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/popup_menu_root"
android:background="#FFFFFF"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
<Button android:id="@+id/popup_menu_button"
android:text="ok"
android:layout_width="fill_parent"
android:layout_height="wrap_content" />
<EditText
android:id="@+id/edittext"
android:layout_width="fill_parent"
android:layout_height="wrap_content"/>
</LinearLayout>
我的活动:
public class MyClass extends Activity {
public String txtCheckin = "???";
private String txtDescription = "???";
private PopupWindow pw;
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
// get the instance of the LayoutInflater
LayoutInflater inflater = (LayoutInflater) MyClass.this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
// inflate our view from the corresponding XML file
final View layout = inflater.inflate(R.layout.popuplayout, (ViewGroup)findViewById(R.id.popup_menu_root));
// create a 100px width and 200px height popup window
pw = new PopupWindow(layout, 100, 200, true);
final EditText edittextDescription = (EditText) findViewById(R.id.edittext);
// set actions to buttons we have in our popup
Button button = (Button)layout.findViewById(R.id.popup_menu_button);
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View vv) {
if (edittextDescription.getText() != null)
{
String newString = edittextDescription.getText().toString();
transmitCheck("MANUAL", txtCheckin, "1", newString);
}
else
{
transmitCheck("MANUAL", txtCheckin, "1", "???");
}
finish();
}
});
}
It seems I can't figure out how to get the text string out of EditText
.
I want to use the text from the EditText
at pressing the button.
layout.xml :
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/popup_menu_root"
android:background="#FFFFFF"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
<Button android:id="@+id/popup_menu_button"
android:text="ok"
android:layout_width="fill_parent"
android:layout_height="wrap_content" />
<EditText
android:id="@+id/edittext"
android:layout_width="fill_parent"
android:layout_height="wrap_content"/>
</LinearLayout>
My Activity :
public class MyClass extends Activity {
public String txtCheckin = "???";
private String txtDescription = "???";
private PopupWindow pw;
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
// get the instance of the LayoutInflater
LayoutInflater inflater = (LayoutInflater) MyClass.this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
// inflate our view from the corresponding XML file
final View layout = inflater.inflate(R.layout.popuplayout, (ViewGroup)findViewById(R.id.popup_menu_root));
// create a 100px width and 200px height popup window
pw = new PopupWindow(layout, 100, 200, true);
final EditText edittextDescription = (EditText) findViewById(R.id.edittext);
// set actions to buttons we have in our popup
Button button = (Button)layout.findViewById(R.id.popup_menu_button);
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View vv) {
if (edittextDescription.getText() != null)
{
String newString = edittextDescription.getText().toString();
transmitCheck("MANUAL", txtCheckin, "1", newString);
}
else
{
transmitCheck("MANUAL", txtCheckin, "1", "???");
}
finish();
}
});
}
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评论(3)
试试这个:
Try this :
自己解决了问题:
必须是
然后我可以这样做来获取字符串
Solved the problem myself:
must be
And then I can do this to get the string