preg_replace 属性值

发布于 2024-10-22 02:06:45 字数 1525 浏览 2 评论 0原文

因此，我有一个有效的 preg_match 模式，用于查找字符串中 HTML 属性的值，并且我需要使用 preg_replace 执行相同的操作 - 不是查找并返回该值，而是将其替换为新值。

但如果我只使用 preg_match 模式，它就不起作用......我被困住了。

代码如下：

    $string = '<object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" 
width="437" height="288" id="viddler">
<param name="movie" value="http://www.viddler.com/player/1234567890/" />
<param name="allowScriptAccess" value="always" />
<param name="allowFullScreen" value="true" />
<param name="flashvars" value="fake=1"/>
<embed src="http://www.viddler.com/player/1234567890/" 
width="437" height="288" type="application/x-shockwave-flash" 
allowScriptAccess="always" allowFullScreen="true" flashvars="fake=1" 
name="viddler" ></embed></object>';

preg_match("|<*[^>]*width=\"([^>]+)\"[^>]*>|Ui", $string, $results);

echo 'Width: '.$results[1];

这有效并将返回 437。如果我在 preg_replace() 函数中使用相同的模式，它将删除整个

非常感谢任何帮助。

编辑：蒂姆的解决方案如下，

我对蒂姆的模式进行了一些小修改：

$interm = preg_replace('|(<*[^>]*width=)"[^>]+"([^>]*>)|Ui', '\1"200"\2', $string);
$result = preg_replace('|(<*[^>]*height=)"[^>]+"([^>]*>)|Ui', '\1"300"\2', $interm);

如果没有此更改，第一个函数将替换宽度，但它会取出标签中此后的每个属性。

感谢蒂姆提供的解决方案！

原文

So I have a working preg_match pattern for finding the value of an HTML attribute in a string, and I need to do the same thing with preg_replace - not find and return the value, but replace it with a new one.

But it doesn't work if I just use the preg_match pattern... I'm stuck.

Here's the code:

    $string = '<object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" 
width="437" height="288" id="viddler">
<param name="movie" value="http://www.viddler.com/player/1234567890/" />
<param name="allowScriptAccess" value="always" />
<param name="allowFullScreen" value="true" />
<param name="flashvars" value="fake=1"/>
<embed src="http://www.viddler.com/player/1234567890/" 
width="437" height="288" type="application/x-shockwave-flash" 
allowScriptAccess="always" allowFullScreen="true" flashvars="fake=1" 
name="viddler" ></embed></object>';

preg_match("|<*[^>]*width=\"([^>]+)\"[^>]*>|Ui", $string, $results);

echo 'Width: '.$results[1];

This works and will return 437. If I use the same pattern in a preg_replace() function though, it will strip out the entire <object> tag. I need to replace that 437 with anything else, say 200. And while we're at it, I need to replace the height value as well. Finally, this should work for any embed code or iframe, so it should just look for width=" or height=", respectively... just like the preg_match example above.

Any help is much appreciated.

EDIT: Tim's solution below

I got Tim's pattern to work with a small modification:

$interm = preg_replace('|(<*[^>]*width=)"[^>]+"([^>]*>)|Ui', '\1"200"\2', $string);
$result = preg_replace('|(<*[^>]*height=)"[^>]+"([^>]*>)|Ui', '\1"300"\2', $interm);

Without this change, the first function replaces the width, but it takes out every attribute after that in the tag.

Thanks to Tim for the solution!

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長街聽風 2024-10-29 02:06:45

您需要捕获要替换的字符串周围的匹配：

由于您想用不同的值替换height和width，因此您需要两个正则表达式，依次应用：

$interm = preg_replace('/(<*[^>]*width=)"[^>]+"([^>]*>)/', '\1"200"\2', $subject);
$result = preg_replace('/(<*[^>]*height=)"[^>]+"([^>]*>)/', '\1"300"\2', $interm);

You need to capture the match around the string to be replaced:

Since you want to replace height and width with different values, you need two regexes, applied sequentially:

$interm = preg_replace('/(<*[^>]*width=)"[^>]+"([^>]*>)/', '\1"200"\2', $subject);
$result = preg_replace('/(<*[^>]*height=)"[^>]+"([^>]*>)/', '\1"300"\2', $interm);

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