Python：如何将终端中打印的内容保存为变量以供以后比较？

发布于 2024-10-22 00:42:17 字数 751 浏览 2 评论 0原文

import imaplib
import pprint

IMAP_SERVER='imap.gmail.com'
IMAP_PORT=993

M = imaplib.IMAP4_SSL(IMAP_SERVER, IMAP_PORT)
rc, resp = M.login('[email protected]', 'password')
print rc, resp

M.select()
for msg_num in M.search(None, "UNDELETED")[1][0].split():
    msg = M.fetch('1', '(BODY.PEEK[TEXT])') 
    print msg[1][0][1][139:161]

M.close()         
M.logout()

我是 python 编程的新手，上面的 python 代码是我用于我想做的程序的代码。当我在终端中运行此命令时，我得到的响应是我已经验证了我的帐户，然后它显示字符 139 和 139 之间的消息。 161，在示例电子邮件中如下：

这只是一个测试...

这在终端中打印出来。我想做的就是将此打印输出与其他内容进行比较。例如：如果a=b则x。我想做的是，如果语句为真则向串口发送信号。

感谢所有帮助，我们感谢并期待任何帮助......

原文

import imaplib
import pprint

IMAP_SERVER='imap.gmail.com'
IMAP_PORT=993

M = imaplib.IMAP4_SSL(IMAP_SERVER, IMAP_PORT)
rc, resp = M.login('[email protected]', 'password')
print rc, resp

M.select()
for msg_num in M.search(None, "UNDELETED")[1][0].split():
    msg = M.fetch('1', '(BODY.PEEK[TEXT])') 
    print msg[1][0][1][139:161]

M.close()         
M.logout()

I'm a new beginner in python programming and the above python code is one that I'm using for a program I want to do. When I run this in a terminal I get the response that I have authenticated my account and then it displays the message between characters 139 & 161, which is the following in the example email:

This is just a test...

This is printed out in the terminal. What I want to do is take this printout and compare it to something else. For example: if a=b then x. What I want to do is that if the statement is true to send a signal to the serial port.

Any help is appreciated and anticipated thanks to all that help...

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姜生凉生 2024-10-29 00:42:17

只需在打印之前将消息分配给一个变量即可：

for msg_num in M.search(None, "UNDELETED")[1][0].split():
    msg = M.fetch('1', '(BODY.PEEK[TEXT])') 
    a = msg[1][0][1][139:161]
    print a

# later..
if a == 'this is just a test...':
   # your code here
   pass

显然，您应该使用比“a”更有意义的变量名称。

Simply assign the message to a variable before you print it:

for msg_num in M.search(None, "UNDELETED")[1][0].split():
    msg = M.fetch('1', '(BODY.PEEK[TEXT])') 
    a = msg[1][0][1][139:161]
    print a

# later..
if a == 'this is just a test...':
   # your code here
   pass

Obviously, you should use a more meaningful variable name than "a".

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