如何查找包含括号“(”并使用单词边界的单词？
我正在大文本中寻找短语“成功（并从失败中学习！）”。由于有括号，我使用 quote(...) 来允许它，但我也想使用单词边界“\b”，因此如果在这样的文本“Kin successes（并从他们的经验中学习）中找到该短语，它将被忽略失败！）”。
这是我的代码：
String phrase = Pattern.quote( "in successes (and learn from their failures!)" );
Pattern myPattern = Pattern.compile( "\\b" + phrase + "\\b" ); // Use word boundary(\b) = No letters after it.
Matcher myMatcher = myPattern.matcher( bigText );
myMatcher.find(); // Returns false.
如上所述，由于使用“\b”，此代码将返回 false。如果我省略“\b”，匹配器将返回 true。 有没有办法在使用两个条件时解决这个问题：quote(...) + "\b"？
I am looking for a phrase "in successes (and learn from their failures!)" in a big text. Since there are brackets i have used quote(...) to allow it, but i also want to use word boundaries "\b" so this phrase will be ignored if it was found in such text "Kin successes (and learn from their failures!)".
Here is my code :
String phrase = Pattern.quote( "in successes (and learn from their failures!)" );
Pattern myPattern = Pattern.compile( "\\b" + phrase + "\\b" ); // Use word boundary(\b) = No letters after it.
Matcher myMatcher = myPattern.matcher( bigText );
myMatcher.find(); // Returns false.
As mentioned this code will return false because of using "\b". If i omitted "\b" the matcher will return true. Is there a way to fix this while using the 2 conditions: quote(...) + "\b" ?
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我认为最好的选择是删除第二个
\b:phrase以!)结尾，它们不是单词字符，并且应该适合所有情况，例如：失败！），以及更多，失败！），失败！）或不如果你想要为了确保它后面没有另一个字母，您可以使用“\\b”+短语+“\\B”，但我不确定这里是否需要它。
The best option here in my opinion is to drop the second
\b:phraseends with!), which aren't word characters, and should match well for all cases, for example:failures!), and more,failures!),failures!)or notIf you want to make sure it isn't followed by another letter you can use
"\\b" + phrase + "\\B", but I'm not sure it's needed here.