JAXP - XSLT 偶发测试失败

发布于 2024-10-21 20:43:31 字数 756 浏览 1 评论 0原文

下面所附的代码会产生零星的测试失败 (JUnit)，在 80% 的时间内有效。我正在使用静态模板对象。如果出现故障，则会将与预期不同的 JAXB 对象放入 Transformer.transform(jaxbSource, result) 方法调用的“结果”中。

我尝试过锁定和同步部分，但没有成功。此外，根据规范，模板对象应该是线程安全的。转变过程中发生了一些奇怪的事情。

错误症状：JUnit 测试失败 - 突然从转换返回错误的对象。

有什么想法吗？

private <S, T> S transform(final Templates template, final Class resultClass, final T data) throws JAXBException, TransformerException {
    Transformer transformer = template.newTransformer();
    final JAXBSource jaxbSource = new JAXBSource(getCachedJAXBContext(data.getClass()), data);
    final Result result = new JAXBResult(getCachedJAXBContext(resultClass));
    transformer.transform(jaxbSource, result);
    return (S) ((JAXBResult) result).getResult();
}

原文

The code attached below produces sporadic test failures (JUnit), works 80% of the time.
I'm using a static Templates object. In the case of failure a different than expected JAXB object is placed into 'result' from the transformer.transform(jaxbSource, result) method call.

I've tried locks and synchronizes sections in vain. Also the Templates object is supposed to be thread safe according to spec. Something weird is happening in the transform.

Error symptom: JUnit test failure - suddenly the wrong object is returned from the transform.

Any ideas?

private <S, T> S transform(final Templates template, final Class resultClass, final T data) throws JAXBException, TransformerException {
    Transformer transformer = template.newTransformer();
    final JAXBSource jaxbSource = new JAXBSource(getCachedJAXBContext(data.getClass()), data);
    final Result result = new JAXBResult(getCachedJAXBContext(resultClass));
    transformer.transform(jaxbSource, result);
    return (S) ((JAXBResult) result).getResult();
}

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静赏你的温柔 2024-10-28 20:43:31

由于您有多个类映射到相同的根元素名称，因此您需要将希望解组的类型作为参数传递给解组操作。这意味着转换为中间表示形式，例如：DOM、byte[]、String 等：

private <S, T> S transform(final Templates template, final Class resultClass, final T data) throws JAXBException, TransformerException {
    Transformer transformer = template.newTransformer();
    final JAXBSource jaxbSource = new JAXBSource(getCachedJAXBContext(data.getClass()), data);
    final Result result = new DOMResult();
    transformer.transform(jaxbSource, result);
    return (S) getCachedJAXBContext(resultClass).createUnmarshaller().unmarshal(new DOMSource(result.getNode()), resultClass).getValue();
}

有关详细信息：

http://bdoughan.blogspot.com/2011/03/handling-duplicate-xmlrootelement.html

Since you have multiple classes mapped to the same root element name, you need to pass the type you wish to unmarshal as a parameter to the unmarshal operation. This will mean transforming to an intermediate representation such as: DOM, byte[], String, etc:

private <S, T> S transform(final Templates template, final Class resultClass, final T data) throws JAXBException, TransformerException {
    Transformer transformer = template.newTransformer();
    final JAXBSource jaxbSource = new JAXBSource(getCachedJAXBContext(data.getClass()), data);
    final Result result = new DOMResult();
    transformer.transform(jaxbSource, result);
    return (S) getCachedJAXBContext(resultClass).createUnmarshaller().unmarshal(new DOMSource(result.getNode()), resultClass).getValue();
}

For more information: