XslCompiledTransform 使用 UTF-16 编码
我有以下代码，我想使用UTF-8编码格式输出xml数据。但它总是以 UTF-16 输出数据：
XslCompiledTransform xslt = new XslCompiledTransform();
xslt.Load(XmlReader.Create(new StringReader(xsltString), new XmlReaderSettings()));
StringBuilder sb = new StringBuilder();
XmlWriterSettings writerSettings = new XmlWriterSettings();
writerSettings.Encoding = Encoding.UTF8;
writerSettings.Indent = true;
xslt.Transform(XmlReader.Create(new StringReader(inputXMLToTransform)), XmlWriter.Create(sb, writerSettings));
I have the following code, which I want to output xml data using the UTF-8 encoding format. but it always outputs data in UTF-16 :
XslCompiledTransform xslt = new XslCompiledTransform();
xslt.Load(XmlReader.Create(new StringReader(xsltString), new XmlReaderSettings()));
StringBuilder sb = new StringBuilder();
XmlWriterSettings writerSettings = new XmlWriterSettings();
writerSettings.Encoding = Encoding.UTF8;
writerSettings.Indent = true;
xslt.Transform(XmlReader.Create(new StringReader(inputXMLToTransform)), XmlWriter.Create(sb, writerSettings));
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XML 输出将包含基于流编码的标头，而不是设置中指定的编码。由于字符串是 16 位 unicode，因此编码将为 UTF-16。解决方法是抑制标头并自己添加它：然后
，当您从 StringBuilder 获取结果时：
The XML output will contain a header that is based on the encoding of the stream, not the encoding specified in the settings. As strings are 16 bit unicode the encoding will be UTF-16. The workaround is to suppress the header and add it yourself instead:
Then when you get the result from the StringBuilder:
如果您使用
MemoryStream代替StringBuilder，则XmlWriter将遵循您在XmlWriterSettings中指定的编码，因为MemoryStream没有像StringBuilder那样的固有编码。If you use a
MemoryStreamin place of theStringBuilder, theXmlWriterwill respect the encoding you specify in theXmlWriterSettings, since theMemoryStreamdoesn't have an inherent encoding like theStringBuilderdoes.