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从 Struts 2 中的 Action 类访问 ApplicationResource.properties 文件

发布于 2024-10-21 13:30:11 字数 78 浏览 0 评论 0原文

我可以从 Struts 2 中的 Action 类访问 ApplicationResource.properties 文件键吗并更新键的值？

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丢了幸福的猪 2024-10-28 13:30:11

我认为您不能直接更新这些键的值，这会破坏它作为（静态）资源的目的。
但是您可以使用占位符。

ApplicationResources.properties

property.key=Hi {0}, there's a problem with {1}

MyAction.java

public ActionForward execute(ActionMapping mapping,
                             ActionForm form,
                             javax.servlet.ServletRequest request,
                             javax.servlet.ServletResponse response)
                      throws java.lang.Exception {
MessageResources msgResource = getResources(request);
String msg = msgResource.getMessage("property.key", "Sankar", "updating values in the resources.");
}

I don't think you can update the values of those keys directly, that would kind of defeat the purpose of it being (static) resources.
You can however use placeholders.

ApplicationResources.properties

property.key=Hi {0}, there's a problem with {1}

MyAction.java

public ActionForward execute(ActionMapping mapping,
                             ActionForm form,
                             javax.servlet.ServletRequest request,
                             javax.servlet.ServletResponse response)
                      throws java.lang.Exception {
MessageResources msgResource = getResources(request);
String msg = msgResource.getMessage("property.key", "Sankar", "updating values in the resources.");
}

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哆兒滾 2024-10-28 13:30:11

是的，这是可能的。
假设您在 applicationResources.properties 文件中有一个属性 error.login 。
例如：error.login=无效的用户名/密码。请再试一次。

然后在 Action 类中，您可以像这样访问它： getText("error.login")

完整示例：

applicationResources.properties

error.login= Invalid Username/Password

LoginAction.java

package net.sumitknath.struts2;

import com.opensymphony.xwork2.ActionSupport;

public class LoginAction extends ActionSupport {

    private String username;

    private String password;

    public String execute() {
        if (this.username.equals("admin") && this.password.equals("admin123")) {
            return "success";
        } else {
            addActionError(getText("error.login"));
            return "error";
        }
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }
}

Yes its possible.
Lets say if you have a property error.login in applicationResources.properties file.
eg : error.login= Invalid Username/Password. Please try again.

then in the Action class you can access it like this : getText("error.login")

Complete example:

applicationResources.properties

error.login= Invalid Username/Password

LoginAction.java

package net.sumitknath.struts2;

import com.opensymphony.xwork2.ActionSupport;

public class LoginAction extends ActionSupport {

    private String username;

    private String password;

    public String execute() {
        if (this.username.equals("admin") && this.password.equals("admin123")) {
            return "success";
        } else {
            addActionError(getText("error.login"));
            return "error";
        }
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }
}

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