绕过规范中的初始化程序
我有以下方法来创建新的 Connection 对象。它将打开一个串行端口。注意，当端口不存在时会失败。
class Connection
def initialize(port)
begin
@serial = SerialPort.new(port, 9600, 8, 1, SerialPort::NONE)
rescue
exit(1)
end
end
def send_command
@serial.write "Something"
end
end
我为此方法编写了 RSpec 规范，到目前为止一切顺利。现在，我想指定下一个方法“send_command”。
问题是我无法在此规范中调用 Connection.new("/some/port") 因为它会失败（端口不存在）。如何绕过创建方法而不存根新方法？如果我理解正确的话，我不允许存根或模拟我正在测试的课程，对吧？
谢谢！
I have the following method to create a new Connection object. It will open a serial port. Note that it will fail when the port does not exist.
class Connection
def initialize(port)
begin
@serial = SerialPort.new(port, 9600, 8, 1, SerialPort::NONE)
rescue
exit(1)
end
end
def send_command
@serial.write "Something"
end
end
I wrote a RSpec spec for this method, so far so good. Now, I would like to spec the next method, "send_command".
The problem is I can not call Connection.new("/some/port") in this spec as it will fail (the port does not exist). How can I bypass the creation method without stubbing the new method? If I understand correctly I am not allowed to stub or mock the class I'm testing, right?
Thanks!
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您可以传入 SerialPort 对象而不是端口号（依赖注入），或具有返回 SerialPort 对象的 create 方法的工厂对象（抽象工厂模式）。然后测试可以在假/模拟/虚拟串行端口或串行端口工厂中通过。
但也许这就是我所说的 C++ 程序员，gnab 的建议似乎更 Rubyish...
You could pass in a SerialPort object instead of a port number (dependency injection), or a factory object that has a create method that returns a SerialPort object (abstract factory pattern). The tests could then pass in a fake/mock/dummy SerialPort or SerialPort factory.
But maybe that is the C++ programmer in me talking, gnab's advice seems to be more Rubyish...
您可以对
SerialPort类的new和write方法进行存根处理。You could stub the
newandwritemethods of theSerialPortclass.这有点 hacky，但您可以调用
Connection.allocate，而不是调用Connection.new。这将创建一个对象而不调用initialize。This is somewhat hacky, but rather than calling
Connection.new, you could callConnection.allocate. This creates an object without callinginitialize.