Python: except EOFError: ... 不起作用

发布于 2024-10-21 08:24:32 字数 472 浏览 1 评论 0原文

我有一个 try/ except 块，用于发送消息并等待客户端的确认。如果客户端终止，pickle 会引发 EOFError，但下面的代码不会捕获该错误并执行正常关闭。相反，它打印堆栈跟踪。我认为它与“除了socket.error，EOFError：”行有关 - 我是否使用错误的语法来处理socket.error和EOFError？

        try:
            msgs = [1]
            self.sock.send(pickle.dumps(msgs))
            rdy = pickle.loads(self.sock.recv(2097152))
        except socket.error, EOFError: 
            print 'log socketmanager closing'
            self.terminate()
            break

原文

I have a try/except block that sends a message and waits for confirmation from client. If the client terminates, pickle raises an EOFError, but the code below does not catch the error and execute the graceful shut down. It instead prints stack trace. I assume it has to do with the line "except socket.error, EOFError:" - am I using the wrong syntax to handle both socket.error and EOFError there?

        try:
            msgs = [1]
            self.sock.send(pickle.dumps(msgs))
            rdy = pickle.loads(self.sock.recv(2097152))
        except socket.error, EOFError: 
            print 'log socketmanager closing'
            self.terminate()
            break

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半衬遮猫 2024-10-28 08:24:33

在 Python 2.x 中，except a, b 形式捕获 a 类型的异常，并将其分配给名为 b 的变量。在您的情况下，这将导致 EOFError 被忽略。请尝试以下操作：

...
except (socket.error, EOFError):
    ...

编辑：详细说明一下，Python 3.0 中的新语法以及 2.6+ 中可用的新语法（尽管不是必需的）用于捕获异常的值是 except a as b。

In Python 2.x, the form except a, b catches an exception of type a and assign it to a variable called b. In your case this would result in EOFError being ignored. Try this instead:

...
except (socket.error, EOFError):
    ...

Edit: to elaborate, the new syntax in Python 3.0, and available, though not required, in 2.6+, for capturing the value of an exception is except a as b.

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