无法使用 PHP 从一个页面获取信息到另一页面

发布于 2024-10-21 06:07:01 字数 2057 浏览 2 评论 0原文

我有两页。一个带有选择框和发送按钮的。当用户从选择框中选择他们的选项并单击“发送”时，会将他们带到输出他们的选择的第二页。

date_change.php

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />

</head>

<body>
<?php
$day = array(range(1,31));
$month = array(range(1,12));
$year = array(range(2011,2020));
?>
<form action="test.php" method="post">
Day:
<select >
  <?php foreach($day[0]++ as $key => $value) { ?>
    <option value="<?php echo $key ?>" name="day"><?php echo $value ?></option>
  <?php }?>
</select>
<br>
Month:
<select>
  <?php foreach($month[0]++ as $key => $value) { ?>
    <option value="<?php echo $key ?>" name="month"><?php echo $value ?></option>
  <?php }?>
</select>
<br>
Year:
<select>
  <?php foreach($year[0]++ as $key => $value) { ?>
    <option value="<?php echo $key ?>" name="year"><?php echo $value ?></option>
  <?php }?>
</select>
<input type='submit' value='send' name='send' />
</form>


</body>
</html>

一旦用户做出选择并单击“发送”，就会将其带到 test.php：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />

</head>

<body>

Date Selected: <?php echo $_POST["day"];echo $_POST["month"];echo $_POST["year"]; ?>

</body>
</html>

但是，即使它转到 test.php 页面，它也不会显示用户选择的内容。有什么帮助吗？

我哪里出错了？

原文

I have two pages. One with the select boxes on and the send button. When the user chooses their options from the select boxes and clicks send it takes them to the second page which outputs their choices.

date_change.php

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />

</head>

<body>
<?php
$day = array(range(1,31));
$month = array(range(1,12));
$year = array(range(2011,2020));
?>
<form action="test.php" method="post">
Day:
<select >
  <?php foreach($day[0]++ as $key => $value) { ?>
    <option value="<?php echo $key ?>" name="day"><?php echo $value ?></option>
  <?php }?>
</select>
<br>
Month:
<select>
  <?php foreach($month[0]++ as $key => $value) { ?>
    <option value="<?php echo $key ?>" name="month"><?php echo $value ?></option>
  <?php }?>
</select>
<br>
Year:
<select>
  <?php foreach($year[0]++ as $key => $value) { ?>
    <option value="<?php echo $key ?>" name="year"><?php echo $value ?></option>
  <?php }?>
</select>
<input type='submit' value='send' name='send' />
</form>


</body>
</html>

Once the user makes their choices and clicks send it takes them to test.php:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />

</head>

<body>

Date Selected: <?php echo $_POST["day"];echo $_POST["month"];echo $_POST["year"]; ?>

</body>
</html>

However, even though it goes to the test.php page it doesnt show what the user picked. Any help?

where am I going wrong?

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芯好空 2024-10-28 06:07:01

您应该将 name 属性添加到

另外，您应该将更改为以获得 XHTML 有效代码。

将您的代码更改为：

Day:
<select name="day">
  <?php foreach($day[0]++ as $key => $value) { ?>
    <option value="<?php echo $key; ?>"><?php echo $value; ?></option>
  <?php } ?>
</select>
<br />
Month:
<select name="month">
  <?php foreach($month[0]++ as $key => $value) { ?>
    <option value="<?php echo $key; ?>"><?php echo $value; ?></option>
  <?php } ?>
</select>
<br />
Year:
<select name="year">
  <?php foreach($year[0]++ as $key => $value) { ?>
    <option value="<?php echo $key; ?>"><?php echo $value; ?></option>
  <?php } ?>
</select>

You should add a name attribute to your <select> tags instead of your <option> tags.

Also, you should change <br> to <br /> for XHTML valid code.

Change you code to:

Day:
<select name="day">
  <?php foreach($day[0]++ as $key => $value) { ?>
    <option value="<?php echo $key; ?>"><?php echo $value; ?></option>
  <?php } ?>
</select>
<br />
Month:
<select name="month">
  <?php foreach($month[0]++ as $key => $value) { ?>
    <option value="<?php echo $key; ?>"><?php echo $value; ?></option>
  <?php } ?>
</select>
<br />
Year:
<select name="year">
  <?php foreach($year[0]++ as $key => $value) { ?>
    <option value="<?php echo $key; ?>"><?php echo $value; ?></option>
  <?php } ?>
</select>

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