全局运算符删除 - 语法

发布于 2024-10-21 01:08:40 字数 452 浏览 1 评论 0原文

我继承了一个不可更改的 C 结构，其中包含指向（分配的）内存的指针。

   typedef struct {
     int id;
     int * val;
   } T;

我想在这些对象上使用 new 和 delete ，并且我想知道是否可以在全局范围内重载删除。我首先无法选择重写结构/类。问题是我找不到正确的语法。这就是我所拥有的 - 它可以编译，但显然会失败，因为该函数应用于所有删除调用：

   void operator delete(void*p) throw() {
     T * t = reinterpret_cast<T*>(p);
     free(p->val);
   }

我是否在尝试不可能的事情？我读过，运算符删除重载不一定是成员函数，但这是否只是提供了一种为所有指针编写通用删除的方法？

原文

I have inherited an unchangeable C struct that contains pointers to (alloc'd) memory.

   typedef struct {
     int id;
     int * val;
   } T;

I would like to use new and delete on these objects, and I was wondering if it was possible to overload delete at global scope. I don't have the option of rewriting the struct / class in the first place. The trouble is I cannot find the correct grammar. This is what I have - it compiles but obviously fails since the function is applied to all delete calls:

   void operator delete(void*p) throw() {
     T * t = reinterpret_cast<T*>(p);
     free(p->val);
   }

Am I attempting the impossible? I have read that the operator delete overload does not have to be a member function, but does that just provide a means to write a generic delete for all pointers?

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三生池水覆流年 2024-10-28 01:08:40

嗯，看起来像是一个大锤方法，如果您只是这个结构的用户，并且担心它的内存管理方面，但又无法修改它，为什么不将它包装在代码中呢？

class Sane_T
{
  public:
   Sane_T() 
   { 
     // do stuff 
   } 

   ~Sane_T()
   {
     // Now cleanup..
     if (_inst.val)
       free(_inst.val);
   }

  private:
    T _inst;
};

Hmm, seems like a sledgehammer approach, if you are simply a user of this structure, and worried about the memory management aspect of it, and yet cannot modify it, why don't you wrap it in your code?

i.e.

class Sane_T
{
  public:
   Sane_T() 
   { 
     // do stuff 
   } 

   ~Sane_T()
   {
     // Now cleanup..
     if (_inst.val)
       free(_inst.val);
   }

  private:
    T _inst;
};

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