复合主键 Hibernate 和 Java 实现
我定义了一个非常简单的数据库,如下所示:
我正在使用 hibernate 插件来生成不同的数据库类,包括客户和订单之间的一对多关系。我将这种关系作为一种识别关系,因为如果没有链接到客户,订单就不会存在。
我有以下三个课程:
=>类客户
private int idCustomer;
private String name;
private Set<Order> orders = new HashSet<Order>(0);
public Customer() {
}
public Customer(int idCustomer) {
this.idCustomer = idCustomer;
}
public Customer(int idCustomer, String name, Set<Order> orders) {
this.idCustomer = idCustomer;
this.name = name;
this.orders = orders;
}
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "idCustomer", unique = true, nullable = false)
public int getIdCustomer() {
return this.idCustomer;
}
public void setIdCustomer(int idCustomer) {
this.idCustomer = idCustomer;
}
@Column(name = "name", length = 45)
public String getName() {
return this.name;
}
public void setName(String name) {
this.name = name;
}
@OneToMany(fetch = FetchType.LAZY, mappedBy = "customer")
public Set<Order> getOrders() {
return this.orders;
}
public void setOrders(Set<Order> orders) {
this.orders = orders;
}
=>班级顺序:
private OrderId id;
private Customer customer;
private String quantity;
private Float price;
public Order() {
}
public Order(OrderId id, Customer customer) {
this.id = id;
this.customer = customer;
}
public Order(OrderId id, Customer customer, String quantity, Float price) {
this.id = id;
this.customer = customer;
this.quantity = quantity;
this.price = price;
}
@EmbeddedId
@AttributeOverrides({
@AttributeOverride(name = "idOrder", column = @Column(name = "idOrder", nullable = false)),
@AttributeOverride(name = "customerIdCustomer", column = @Column(name = "Customer_idCustomer", nullable = false)) })
public OrderId getId() {
return this.id;
}
public void setId(OrderId id) {
this.id = id;
}
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "Customer_idCustomer", nullable = false, insertable = false, updatable = false)
public Customer getCustomer() {
return this.customer;
}
public void setCustomer(Customer customer) {
this.customer = customer;
}
@Column(name = "quantity", length = 45)
public String getQuantity() {
return this.quantity;
}
public void setQuantity(String quantity) {
this.quantity = quantity;
}
@Column(name = "price", precision = 12, scale = 0)
public Float getPrice() {
return this.price;
}
public void setPrice(Float price) {
this.price = price;
}
=> Class OrderId
private int idOrder;
private int customerIdCustomer;
public OrderId() {
}
public OrderId(int idOrder, int customerIdCustomer) {
this.idOrder = idOrder;
this.customerIdCustomer = customerIdCustomer;
}
@Column(name = "idOrder", nullable = false)
public int getIdOrder() {
return this.idOrder;
}
public void setIdOrder(int idOrder) {
this.idOrder = idOrder;
}
@Column(name = "Customer_idCustomer", nullable = false)
public int getCustomerIdCustomer() {
return this.customerIdCustomer;
}
public void setCustomerIdCustomer(int customerIdCustomer) {
this.customerIdCustomer = customerIdCustomer;
}
public boolean equals(Object other) {
if ((this == other))
return true;
if ((other == null))
return false;
if (!(other instanceof OrderId))
return false;
OrderId castOther = (OrderId) other;
return (this.getIdOrder() == castOther.getIdOrder())
&& (this.getCustomerIdCustomer() == castOther
.getCustomerIdCustomer());
}
public int hashCode() {
int result = 17;
result = 37 * result + this.getIdOrder();
result = 37 * result + this.getCustomerIdCustomer();
return result;
}
然后我有我的主类:
public static void main(String[] args) {
Customer customer = new Customer();
customer.setName("John Doe");
CustomerDAO.save(customer);
Order order = new Order();
order.setQuantity(10);
order.setPrice(100);
order.setCustomer(customer);
OrderDAO.save(order);
}
请注意,我的 DAO 对象没有做任何花哨的事情...只是获取会话的常用 HibernateUtil 实现并最终调用“保存”方法。我的问题如下。我以前从未处理过复合键...请提前原谅我的愚蠢问题。我不想手动处理不同的 id 和主键。对于 Cutomer 类,这不是问题,因为我设置了一个策略,在保存到数据库时会自动创建 id。对于 Order 类,我也不想处理这个问题。但由于密钥是复合的,Hibernate 在尝试将此对象保存在数据库中时会生成一个identifierGenerationExeption...我想要的是以下 =>自动生成的订单 ID,因为我在订单对象中设置了客户,所以我希望 Hibernate 将客户 ID 链接到组合键中的 ID...执行此操作的正确方法是什么?
谢谢
I have defined a very simple database as follow :
I'm using the hibernate plug-in to generate the different classes, including the one-to-many relationship between customer and order. i made this relationship as an identifying relationship as an order could not exist if not linked to a customer.
I have the three following classes :
=> Class Customer
private int idCustomer;
private String name;
private Set<Order> orders = new HashSet<Order>(0);
public Customer() {
}
public Customer(int idCustomer) {
this.idCustomer = idCustomer;
}
public Customer(int idCustomer, String name, Set<Order> orders) {
this.idCustomer = idCustomer;
this.name = name;
this.orders = orders;
}
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "idCustomer", unique = true, nullable = false)
public int getIdCustomer() {
return this.idCustomer;
}
public void setIdCustomer(int idCustomer) {
this.idCustomer = idCustomer;
}
@Column(name = "name", length = 45)
public String getName() {
return this.name;
}
public void setName(String name) {
this.name = name;
}
@OneToMany(fetch = FetchType.LAZY, mappedBy = "customer")
public Set<Order> getOrders() {
return this.orders;
}
public void setOrders(Set<Order> orders) {
this.orders = orders;
}
=> Class Order :
private OrderId id;
private Customer customer;
private String quantity;
private Float price;
public Order() {
}
public Order(OrderId id, Customer customer) {
this.id = id;
this.customer = customer;
}
public Order(OrderId id, Customer customer, String quantity, Float price) {
this.id = id;
this.customer = customer;
this.quantity = quantity;
this.price = price;
}
@EmbeddedId
@AttributeOverrides({
@AttributeOverride(name = "idOrder", column = @Column(name = "idOrder", nullable = false)),
@AttributeOverride(name = "customerIdCustomer", column = @Column(name = "Customer_idCustomer", nullable = false)) })
public OrderId getId() {
return this.id;
}
public void setId(OrderId id) {
this.id = id;
}
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "Customer_idCustomer", nullable = false, insertable = false, updatable = false)
public Customer getCustomer() {
return this.customer;
}
public void setCustomer(Customer customer) {
this.customer = customer;
}
@Column(name = "quantity", length = 45)
public String getQuantity() {
return this.quantity;
}
public void setQuantity(String quantity) {
this.quantity = quantity;
}
@Column(name = "price", precision = 12, scale = 0)
public Float getPrice() {
return this.price;
}
public void setPrice(Float price) {
this.price = price;
}
=> Class OrderId
private int idOrder;
private int customerIdCustomer;
public OrderId() {
}
public OrderId(int idOrder, int customerIdCustomer) {
this.idOrder = idOrder;
this.customerIdCustomer = customerIdCustomer;
}
@Column(name = "idOrder", nullable = false)
public int getIdOrder() {
return this.idOrder;
}
public void setIdOrder(int idOrder) {
this.idOrder = idOrder;
}
@Column(name = "Customer_idCustomer", nullable = false)
public int getCustomerIdCustomer() {
return this.customerIdCustomer;
}
public void setCustomerIdCustomer(int customerIdCustomer) {
this.customerIdCustomer = customerIdCustomer;
}
public boolean equals(Object other) {
if ((this == other))
return true;
if ((other == null))
return false;
if (!(other instanceof OrderId))
return false;
OrderId castOther = (OrderId) other;
return (this.getIdOrder() == castOther.getIdOrder())
&& (this.getCustomerIdCustomer() == castOther
.getCustomerIdCustomer());
}
public int hashCode() {
int result = 17;
result = 37 * result + this.getIdOrder();
result = 37 * result + this.getCustomerIdCustomer();
return result;
}
I then have my main class :
public static void main(String[] args) {
Customer customer = new Customer();
customer.setName("John Doe");
CustomerDAO.save(customer);
Order order = new Order();
order.setQuantity(10);
order.setPrice(100);
order.setCustomer(customer);
OrderDAO.save(order);
}
Please note that my DAO objects are doing nothing fancy... Just the usual HibernateUtil implementation of getting the session and finally call the 'save' method. My Problem is the following. I have never dealt before with composite key... Excuse me for my stupid question in advance. I don't want to deal manually with the different ids and primary keys. For the Cutomer class, it is not a problem since I set up a strategy that will automatically create the id when saving in database. For the Order class, I don't want to deal with that as well. But since the key is composite, Hibernate generates an identifierGenerationExeption when trying to save this object in DB... What I would have liked is the following => an Order id generated automatically and since I setup the customer in the order Object, I would have expect hibernate to link the customer id to the one in the composite key... What is the correct way of doing this thing ?
Thanks
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(2)
为什么要在 Order 实体的主键中包含客户 ID 外键?它的主键应该是
idOrder
。Customer_idCustomer
应该是外键,并且不应该是订单 ID 的一部分。Why do you include the customer ID foreign key in the primary key of your Order entity? Its primary key should be
idOrder
.Customer_idCustomer
should be a foreign key, and should not be part of the ID of Order.不鼓励使用复合键,并且仅应在被迫时使用(例如:遗留数据库)。我认为您应该将订单中的
Customer_id
设置为not null
。订单有一个简单、常规的 ID (idOrder
),一切都应该很简单。Using composite keys is discouraged and should only be used when forced to do it (say: legacy database). I think that you just should make the
Customer_id
in the Ordernot null
. There is a simple, regular id for the order (idOrder
) and everything should be straight forward.