c++：字符串流到向量

发布于 2024-10-20 21:28:34 字数 557 浏览 5 评论 0原文

我正在尝试将字符串流中的数据存储到向量中。我可以成功地这样做，但它会忽略字符串中的空格。如何才能将空格也推入向量中？

谢谢！

代码存根：

#include <iostream>
#include <sstream>
#include <vector>

using namespace std;

int main()
{
    stringstream s;
    string line  = "HELLO HELLO\0";

    stringstream stream(line);

    unsigned char temp;
    vector<unsigned char> vec;
    while(stream >> temp) 
        vec.push_back(temp);


    for (int i = 0; i < vec.size(); i++)
         cout << vec[i];
    cout << endl;
    return 0;
}

原文

I'm trying to store the data that is in a stringstream into a vector. I can succesfully do so but it ignores the spaces in the string. How do I make it so the spaces are also pushed into the vector?

Thanks!

Code stub:

#include <iostream>
#include <sstream>
#include <vector>

using namespace std;

int main()
{
    stringstream s;
    string line  = "HELLO HELLO\0";

    stringstream stream(line);

    unsigned char temp;
    vector<unsigned char> vec;
    while(stream >> temp) 
        vec.push_back(temp);


    for (int i = 0; i < vec.size(); i++)
         cout << vec[i];
    cout << endl;
    return 0;
}

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

星 2024-10-27 21:28:34

为什么使用stringstream从string复制到vector？你可以这样做：

vector<unsigned char> vec(line.begin(), line.end());

这将直接进行复制。如果需要使用stringstream，则需要使用stream >>首先是 noskipws。

Why are you using a stringstream to copy from a string into a vector<unsigned char>? You can just do:

vector<unsigned char> vec(line.begin(), line.end());

and that will do the copy directly. If you need to use a stringstream, you need to use stream >> noskipws first.

回复收藏 0 原文

冬天旳寂寞 2024-10-27 21:28:34

默认情况下，标准流都跳过空格。如果您希望禁用跳过空白，您可以使用 noskipws 操纵器在下一个流提取 (>>) 操作中明确执行此操作，如下所示：

stream >> std::noskipws >> var;

By default, the standard streams all skip whitespace. If you wish to disable the skipping of white space you can explicitly do so on the next stream extraction (>>) operation by using the noskipws manipulator like so: