尝试将列表与 Django 中的 DateTimeField 和日期对象结合起来
我有 2 个带有 Title 和 Created_At DateTimeField （文章和项目）的 Django 查询列表，我还有另一个列表，它是返回字符串 Title 和 Create_At 日期对象的 python 函数的结果。
我想将这些列表链接在一起，以便可以将它们组合起来并按日期字段对结果进行排序 - 但是目前我收到以下错误：
can't compare datetime.datetime to tuple
如何将这两个列表放在一起？导致错误的代码是：
latest_changes = sorted(
chain(articles, projects, tweets),
key=lambda instance: instance.created)
OR是否有更好的方法来执行此操作而不是使用链？理想情况下，我想创建一个新列表，而不必使各个列表字段名称也匹配（我收集类似名称的链匹配项）。
I've got 2 Django query lists with a Title and a Created_At DateTimeField (Articles and Projects), I have another list which is the result of a python function that returns a string Title and a Create_At date object.
I want to chain these lists together so I can combine them and sort the results by their Date fields - however at the moment I'm getting the following error:
can't compare datetime.datetime to tuple
How do I get these two lists together? The code causing the error is:
latest_changes = sorted(
chain(articles, projects, tweets),
key=lambda instance: instance.created)
OR Is there a better way to do this instead of using chain? Ideally I'd like to create a new list without having to have the individual list field names matching as well (I gather chain matches like to like on names).
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评论（2）
我认为 tweets.created 是一个元组而不是 Datetime 对象。您可以使用 dateutil 模块将元组转换为 python 中正确的 Datetime 对象，然后您可以无缝比较:)
I think the tweets.created is a tuple rather than a Datetime object. You can use the dateutil module to convert the tuple into a proper Datetime object in python and then you can compare seamlessly :)
从错误消息来看，显然
instance.created是链式可迭代对象之一的元组。我的猜测是，它是您所讨论的“返回字符串 Title 和 Create_At 日期对象的 python 函数的结果”的项目，因为
DateTimeField不会返回元组。type(tweets[0].created) == tuple返回True吗？Judging by the error message, apparently
instance.createdis a tuple for one of your chained iterables.My guess is that it's whichever item is the "result of a python function that returns a string Title and Create_At date object" that you were talking about, as a
DateTimeFieldwouldn't return a tuple.Does
type(tweets[0].created) == tuplereturnTrue?