将纬度和经度坐标发送到应用程序委托中的 didFinishLaunchingWithOptions

Question

我有一个函数可以在我的应用程序委托中获取纬度和经度，并且工作正常：

- (void)newPhysicalLocation:(CLLocation *)location {

    // Store for later use
    self.lastKnownLocation = location;

    // Remove spinner from view
    for (UIView *v in [self.viewController.view subviews])
    {
        if ([v class] == [UIActivityIndicatorView class])
        {
            [v removeFromSuperview];
            break;
        }
    }

    // Alert user
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Location Found" message:[NSString stringWithFormat:@"Found physical location.  %f %f", self.lastKnownLocation.coordinate.latitude, self.lastKnownLocation.coordinate.longitude] delegate:self cancelButtonTitle:@"OK" otherButtonTitles: nil];
    [alert show];
    [alert release];  

    currentLatitude = (self.lastKnownLocation.coordinate.latitude);
    NSLog(@"current latitude: %f",self.lastKnownLocation.coordinate.latitude);


    currentLongitude = (self.lastKnownLocation.coordinate.longitude);
    NSLog(@"current longitude: %f",currentLongitude);
}

但是，我试图将 currentLatitude 和 currentLongitude 值发送到 didFinishLaunchingWithOptions 部分中应用程序委托的顶部。我正在尝试执行此操作，以便可以将这些值传递到我已设置的另一个 viewController：

MyAppDelegate *appDelegate = (MyAppDelegate *)[[UIApplication sharedApplication] delegate];

我可以将 currentLatitude 和 currentLongitude 值发送到 didFinishLaunchingWithOptions 部分吗？

Answer 1

为什么不在第二个 viewController 中创建 currentLatitude 和 currentLongitude 呢？

您可以使用

- (void)newPhysicalLocation:(CLLocation *)location {
    // your code here

    SecondViewController *viewController = [[SecondViewController alloc] init];
    [viewController setLatitude: currentLatitude andLongitude: currentLongitude];
}

或仅

[viewController setCurrentLatitude: currentLatitude];
[viewController setCurrentLongitude: currentLongitude];

Answer 2

根据我对你的问题的理解，你想将这些坐标值传递给另一个视图控制器。如果是这种情况，您可以将 currentLatitude 和 currentLongitude 作为应用程序委托的类变量。然后，当您在 applicationDidFinishLaunchingWithOptions: 中调用此函数时，您可以将值分配给这些类变量。然后您可以通过应用程序委托的实例在任何地方访问这些变量。

注意：如果您想在类外部访问变量，则必须合成变量。

希望这有帮助